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Sveta_85 [38]
4 years ago
10

Please help me for the whole page!

Mathematics
2 answers:
Ksenya-84 [330]4 years ago
6 0
1.B
2.B
3.A 
4.A
5.A
6.C

i am not sure about  3 because if you chose A. as your answer you would still need another bus. so for 3 it could be A. or B.

jasenka [17]4 years ago
5 0
Answer to number 6 is D because to compare you need to add zeros to the end for ex.(.4_.78 = .40_.78
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3 years ago
One positive integer is 1 less than twice another. The sum of their squares is 106. Find the integers.
neonofarm [45]
They give us 2 pieces to the puzzle.  Both are positive numbers...x and y.
1.) 1 number is 1 less than twice another number. (x = 2y -1)...and
2.) the sum of their squares is 106.  (x^2 + y^2 = 106).

 substitute the value for x into the second equation.

(2y-1)^2 + y^2 = 106
(2y-1) (2y-1) + y^2 = 106  (use distributive property)
4y^2 - 2y - 2y + 1 + y^2 = 106  (subtract 106 from both sides)
4y^2 - 2y - 2y + 1 + y^2 - 106 = 106 - 106 (combine like terms)
5y^2 - 4y - 105 = 0  (factor)
(y-5) (5y-21) = 0  (set to 0)
y - 5 = 0
y = 5 

substitute the 5 into the equation for y   (x = 2(5) - 1)
           x = 9   if we square 9, we get 81.
subtracted from 106 we have 25...the square root of 25 is 5.

our answers are 5 and 9.
8 0
4 years ago
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