Answer:
first find the surface area of one of the square and one of the triangle.
then multiple it by the number of square and triangle they have
finally add the total surface area of the triangle with the total surface area of the square.
Step-by-step explanation:
- for one square
area= base * width
= 10*10
=100
total area of square= number of square * area of one square
t=6*100
t=600
area = 1/2 base * height
= 1/2 *10*8.66
=43.3
total area of triangle=number of triangle* area of one triangle
t2=8*43.3
=346.4
total surface area= total surface area of the square+ total surface area of the triangle
=600+346.4
=946.4 in^2
The area of a hexagon is
A= a^2 (3√3)/2
we replace a with 4
A=41.57
Solve:-
Write it down again:-
3 · 3 · x · x · x · x
We will write it like this:-
3 · 3 · x³
Answer:
there are no values of S
that make the equation true.
No solution
Step-by-step explanation:
The answer is 200 cm³
The volume of the rectangular prism (V1) is:
V1 = l · w · h (l - length, w - width, h - height)
It is given:
h = 12 cm
w = l = 5 cm (since it has a square base which all sides are the same size).
Thus: V1 = 12 · 5 · 5 = 300 cm³
The volume of pyramid (V2) is:
V2 = 1/3 · l · w · h (l - length, w - width, h - height)
It is given:
h = 12 cm
w = l = 5 cm (since it has a square base which all sides are the same size).
V2 = 1/3 · 12 · 5 · 5 = 1/3 · 300 = 100 cm³
The volume of the space outside the pyramid but inside the prism (V) is a difference between the volume of the rectangular prism (V1) and the volume of the pyramid (V2):
V = V1 - V2 = 300 cm³ - 100 cm³ = 200 cm³
