All categories

3 years ago

Never mind no question her

Mathematics

2 answers:

Phantasy [73]3 years ago

8 0

Answer:

Step-by-step explanation:

Norma-Jean [14]3 years ago

5 0

Answer:

LMA_OO

Step-by-step explanation:

hahah

You might be interested in

Otis measured the heights of several sunflowers. He found that their heights were 1, 4, 6, 9, and 10 feet. Otis found that the m

lisabon 2012 [21]

Answer: 6 feet describes the center, and 9 feet describes the spread

Step-by-step explanation:

The center of a data set is mostly considered as the median or the mean

Here mean is 6 (given). And median is also 6. As 6 is exactly at the middle of the data set. (When arranged in ascending order)

Now, one of the way of calculating the spread is calculating the range, here it's given that the range is 9.

Therefore, 6 feet describes the center, and 9 feet describes the spread is correct.

3 0

2 years ago

What’s is the perimeter of the following figure

NARA [144]

Answer:

Step-by-step explanation:

7 0

3 years ago

Exercice 5 (2 points)

yulyashka [42]

Answer:

Hours = 2.5

Minutes = 0.04167

I hope it helps. (j'espère que ça aide)

3 0

3 years ago

Find the slope of the line passing through the points (-4,-4) and (2, 5).

mrs_skeptik [129]

Answer:

the slope of the line passing through the points (-4,-4) and (2, 5) m=3/2.

Step-by-step explanation:

Hello!

To find the slope between two points use the formula

m=(y₂-y₁)/(x₂-x₁)... substitute values
m=(5-(-4))/(2-(-4))
m=9/6
m=3/2

7 0

2 years ago

I don’t know how to solve this

Lady_Fox [76]

Answer:

$\theta =2\pi k,\ \ k\in Z\ \\\text{or}\ \\\theta=-\dfrac{2\pi}{3}+2\pi k,\ \ k\in Z$

Step-by-step explanation:

Given:

$\cos \theta-\sqrt{3}\sin \theta=1$

Divide this equation by 2:

$\dfrac{1}{2}\cos \theta-\dfrac{\sqrt{3}}{2}\sin \theta=\dfrac{1}{2}$

Note that

$\cos \dfrac{\pi }{3}=\dfrac{1}{2}\\ \\\sin \dfrac{\pi }{3}=\dfrac{\sqrt{3}}{2}$

So, the previous equation is

$\cos \dfrac{\pi}{3}\cdot \cos \theta-\sin \dfrac{\pi}{3}\cdot \sin \theta=\dfrac{1}{2}$

Remind that

$\cos x\cos y-\sin x\sin y=\cos (x+y),$

then

$\cos \left(\dfrac{\pi}{3}+\theta\right)=\dfrac{1}{2}$

The solution of this equation is

$\dfrac{\pi}{3}+\theta=\pm \arccos \dfrac{1}{2}+2\pi k,\ \ k\in Z\\ \\\dfrac{\pi}{3}+\theta=\pm \dfrac{\pi}{3}+2\pi k,\ \ k\in Z\\ \\\theta =2\pi k,\ \ k\in Z\ \text{or}\ \theta=-\dfrac{2\pi}{3}+2\pi k,\ \ k\in Z$

8 0

3 years ago