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11Alexandr11 [23.1K]
3 years ago
15

Help me with this question

Mathematics
2 answers:
TEA [102]3 years ago
5 0

Answer:

the second one

Step-by-step explanation:

Blizzard [7]3 years ago
3 0
Answer:

B

Explanation:


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A transformer increases the input voltage from 12V to 12,000V. What is the ratio of the number of wire turns on the primary coil
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Answer:

\frac{n_p}{n_s}=\frac{1}{1000}

Step-by-step explanation:

Given voltage of primary coil is V_p=12V

And voltage of secondary coil is V_s=12,000V

A transformer is a device that contains primary and secondary coil. These coils are mounted on soft iron. The change in voltage depends upon the number of turns of primary coil (n_p) and secondary coil (n_s).

Following equation represents the relation between them.

\frac{V_s}{V_p} =\frac{n_s}{n_p}\\\\\frac{12,000}{12}=\frac{n_s}{n_p}\\\\1000=\frac{n_s}{n_p}

Then, ratio of the number of wire turns on the primary coil to the number of turns on the secondary coil is

\frac{n_p}{n_s}=\frac{1}{1000}

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