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3 years ago

Given that a triangle has two sides of lengths 5 inches and 7 inches, which is a possible length of the third side?

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

6 0

Answer: it’s 13

because 13-7-5= 1

12-5-7=0 which is invalid

7-5-2=0 which is invalid

7-5-3=-1 which is invalid

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When pricing out a menu, we know it is important to use the Edible a portion Price. What would the effect on your profit margin

Colt1911 [192]

The effect of Edible a portion Price on your profit margin , if we only use the as purchased price to determine our cost and selling price is that it will maximize the profit because it will account for every part of the production.

<h3>What is edible portion cost?</h3>

The portion cost can be calculated by multiplying the cost of a usable kg with the portion size.

This can be represented as : portion cost = (portion size x cost of usable kg)

It should be noted that Edible portion (EP) serves as the portion of food which will be given top the customer after the preparation.

Learn more about profit margin at:

brainly.com/question/8189926

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6 0

2 years ago

Estimate the answer by rounding. 453 + 158 + 204 + 555 + 361

son4ous [18]

I would say 1700 , I hope this helps

4 0

3 years ago

Read 2 more answers

I have 5 questions, and i need answers ASAP!

Zina [86]

1) 5z-9
2) 7q+12
3) 5.4n-1
4) w+2
5) 8x+2

3 0

3 years ago

There are 1800 gym members in total, 3/4 are aged 25-59, 1/5 are over 60 and the remainder are under 25, how many members are un

siniylev [52]

If $x$ is the number of members under 25, then we have

$1800=\dfrac34\cdot1800+\dfrac15\cdot1800+x\implies x=90$

8 0

3 years ago

You are given the following equation.

saul85 [17]

Answer:

Step-by-step explanation:

Given the equation 4x²+ 49y² = 196

a) Differentiating implicitly with respect to y, we have;

$8x + 98y\frac{dy}{dx} = 0\\98y\frac{dy}{dx} = -8x\\49y\frac{dy}{dx} = -4x\\\frac{dy}{dx} = \frac{-4x}{49y}$

b) To solve the equation explicitly for y and differentiate to get dy/dx in terms of x,

First let is make y the subject of the formula from the equation;

If 4x²+ 49y² = 196

49y² = 196 - 4x²

$y^{2} = \frac{196}{49} - \frac{4x^{2} }{49} \\y = \sqrt{\frac{196}{49} - \frac{4x^{2} }{49} \\} \\$

Differentiating y with respect to x using the chain rule;

Let $u= \frac{196}{49} - \frac{4x^{2} }{49}$

$y = \sqrt{u} \\y =u^{1/2} \\$

$\frac{dy}{dx} = \frac{dy}{du} * \frac{du}{dx}$

$\frac{dy}{du} = \frac{1}{2}u^{-1/2} \\$

$\frac{du}{dx} = 0 - \frac{8x}{49} \\\frac{du}{dx} =\frac{-8x}{49} \\\frac{dy}{dx} = \frac{1}{2} ( \frac{196}{49} - \frac{4x^{2} }{49})^{-1/2} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} ( \frac{196-4x^{2} }{49})^{-1/2} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} ( \sqrt{ \frac{49}{196-4x^{2} })} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} *{ \frac{7}\sqrt {196-4x^{2} }} * \frac{-8x}{49}\\$

$\frac{dy}{dx} = \frac{-4x}{7\sqrt{196-4x^{2} } }$

c) From the solution of the implicit differentiation in (a)

$\frac{dy}{dx} = \frac{-4x}{49y}$

Substituting $y = \sqrt{\frac{196}{49} - \frac{4x^{2} }{49} \\$ into the equation to confirm the answer of (b) can be shown as follows

$\frac{dy}{dx} = \frac{-4x}{49\sqrt{\frac{196-4x^{2} }{49} } }\\\frac{dy}{dx} = \frac{-4x}{49\sqrt{196-4x^{2}}/7} }\\\\\frac{dy}{dx} = \frac{-4x}{7\sqrt{196-4x^{2}}}$

This shows that the answer in a and b are consistent.

6 0

3 years ago