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3 years ago

Will give brainliest. Find the length and measure of each arc. Show your work.

Mathematics

1 answer:

Verdich [7]3 years ago

6 0

Answer:

exact arc length = 21pi

approximate arc length (using calculator) = 65.9734457253857

approximate arc length (using 3.14 for pi) = 65.94

units are in feet

============================================

Work Shown:

L = (x/360)*2*pi*r

L = (315/360)*2*pi*12

L = 21pi = exact arc length in terms of pi

If you use your calculator's stored version of pi, then L is approximately

L = 21pi

L = 65.9734457253857

Or if you end up using pi = 3.14, then

L = 21*pi

L = 21*3.14

L = 65.94

Fairly close to the other approximation though a bit off because pi = 3.14 is just a rough approximation.

You might be interested in

In how many ways can the letters of the word ``COPYRIGHT'' be arranged?

PilotLPTM [1.2K]

Answer:

362,880 ways

Step-by-step explanation:

There are 9 letters so 9!

And none of them are repeated so 9!/0!

9! = 362,880

I hope this helps, and plz mark me brainliest!!

4 0

3 years ago

A farmer fills his field proportionately with soybeans and corn. Last year he planted 200 acres of corn and 50 acres of soybeans

malfutka [58]

Answer:

Part A) Is a directly proportional

Part B) The constant of proportionality is $k=0.25$

Part C) The equation is $y=0.25x$

Part D) $62.5$ acres of soybeans

Step-by-step explanation:

Part A) Are the number of acres of corn and the number of acres of soybeans directly proportional or inversely proportional?

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$

Let

x-----> the number of acres of corn

y----> the number of acres of soybeans

$y/x=k$

if the number of acres of corn increases then the number of acres of soybeans increases

if the number of acres of corn decreases then the number of acres of soybeans decreases

therefore

The relationship is a directly proportional

Part B) What is the constant of proportionality?

we have that

For x=200, y=50

substitute

$y/x=k$

$k=50/200$

$k=0.25$

Part C) Let x equal the number of acres of corn and y equal the number of acres of soybeans. Write an equation to show this relationship.

The linear equation that represent the direct variation is equal to

$y/x=k$

we have

$k=0.25$

substitute

$y/x=0.25$

$y=0.25x$

Part D) How many acres of soybeans can the farmer plant this year if he plants 250 acres of corn?

For x=250

Find the value of y

substitute in the linear equation the value of x and solve for y

$y=0.25(250)=62.5$ -----> acres of soybeans

7 0

3 years ago

For your friend's birthday, you have 3 presents to wrap. Find the combined surface area of these 3 gifts so you know how much wr

omeli [17]

The answer is: 5,614 square inches.

The explanation is shown below:

1. The gift on the bottom is a rectangular prism. To calculate its surface area, you must apply the following formula:

$SA=2[(l)(w)+(l)(h)+(h)(w)]$

Where $l$ is the length (20 inches), $w$ is the width (42 inches) and $h$ is the heigth (16 inches).

2. Substitute values:

$SA1=2[(20in)(42in)+(20in)(16in)+(16in)(42in)]=3,664in^{2$

3. The surface area of the other gifts can be calculated with the formula for calculate the surface area of a cube:

$SA=6s^{2}$

Where $s$ is the side.

4. The surface area of the bigger cube is:

$SA2=6(15in^{2})=1,350in^{2}$

5. The surface area of the smaller cube is:

$SA3=6(10in^{2})=600in^{2}$

6. The total surface area (the combined surface area of the three gifts) is:

$SAt=SA1+SA2+SA3\\SAt=3,664in^{2}+1,350in^{2}+600in^{2}\\SAt=5,614in^{2}$

7 0

3 years ago

The graph of y=1/x is shown below. Draw the graph of its inverse.

lord [1]

Y=1/x solve for x

x=1/y now reverse lables...

y=1/x

Yes that is the same equation you started with. What that means is the the inverse function in this case produces the same exact graph :)

4 0

4 years ago

Read 2 more answers

Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).

fomenos

Answer:

$\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1$

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is $2a=|4--10|$ .

$\implies 2a=|14|$

$\implies 2a=14$

$\implies a=7$

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is $(\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)$

We need to use the relation $a^2+b^2=c^2$ to find $b^2$ .

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

$c=|6--3|=9$

$\implies 7^2+b^2=9^2$

$\implies b^2=9^2-7^2$

$\implies b^2=81-49$

$\implies b^2=32$

We substitute these values into the standard equation of the hyperbola to obtain:

$\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1$

$\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1$

7 0

3 years ago