Moving from a to b, the x component of the desired vector is 7-(-9) = 16, and
the y component is 3-9 = -6.
So the vector from a to b is <16,-6>, and the magnitude is
sqrt(16^2 + (-6)^2 ), applying the Pythagorean Theorem.
If at least one has to be heads then it would be 1/5
The possible base and height of a second triangle are 12 and 7, respectively
<h3>How to determine the possible base and height of a second triangle?</h3>
An inverse variation is represented as:
Base * Height = k
Where k is the constant of variation.
In this case, k is the area
So, we have:
Base * Height = Area
For the first triangle, we have:
14 * 6 = Area
Evaluate
Area = 84
Substitute Area = 84 in Base * Height = Area
Base * Height = 84
Express 84 as the product of two numbers
Base * Height = 12 * 7
By comparison;
Base =12 and Height = 7
Hence, the possible base and height of a second triangle are 12 and 7, respectively
Read more about variation at:
brainly.com/question/6499629
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Answer:
x = -9
Step-by-step explanation:
3^4х = 27^(x-3)
Replace 27 with 3^3
3^4х = 3^3^(x-3)
We know that a^b^c = a^ (b*c)
3^4х = 3^(3(x-3))
Since the bases are the same, the exponents are the same
4x = 3(x-3)
Distribute
4x =3x-9
Subtract 3x from each side
4x-3x = 3x-3x-9
x = -9
Answer
The value of x is 6.2 units .
Step-by-step explanation:
Now by using the pythagorean theorem
Hypotenuse² = Perpendicular² + Base²
Now in the Δ ABD
As given
DB² = DA² + AB²
As given
DB = 13 units
AB = 9 units
Putting values in the above
13² = 9²+ DA²
169 - 81 = DA²
88 = DA²
In ΔABC
AB² = AC² + CB²
(As given AB = 9 units , CB = x)
9² = AC² + x²
AC ² = 81 - x²
Now in ΔADC.
AD² = AC² + DC ²
As
AC ² = 81 - x²
DC = 13 - x
(By using the formula (a + b)² = a² + b² + 2ab )
88-81 - 169 = -26x
88-250 =-26x
-162 = - 26x
x = 6.2 (Approx)
Therefore the value of x is 6.2 units .
