Parker has $2,500 in her bank account that earns 3.8% interest annually. How much money will she have in her bank account after
2 answers:
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Answer:
The lengths of sides of squares are 5 cm and 9 cm.
Step-by-step explanation:
Let the sides of rectangle be x and y .
Area of rectangle = Length × Breadth
Given : Area of rectangle = 45 cm².
⇒ x × y = 45
⇒ ........(1)
Two squares are constructed such that two adjacent sides of the rectangle
so squares have side x and y .
Area of square = side × side
Area of square with side x = x²
Area of square with side y = y²
Also, The combined area of the two squares is 106 cm².
⇒ x² + y² = 106
From (1) put value of x , we get,
Solving for y ,
or
on solving we get y = 5 and y = 9
Also, x can be find by putting in (1),
⇒ and ⇒
⇒ x = 9 and x = 5
Thus, lengths of sides of squares are 5 cm and 9 cm.
The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11
⇒x=11t
Area of square=
Area of square={as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
Learn more about The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11
⇒x=11t
Area of square=
Area of square={as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
Learn more about area here:
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Answer:
The 90% confidence interval for the mean time required by all college graduates is between 5.36 years and 5.44 years.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 5.4 - 0.04 = 5.36 years.
The upper end of the interval is the sample mean added to M. So it is 5.4 + 0.04 = 5.44 years.
The 90% confidence interval for the mean time required by all college graduates is between 5.36 years and 5.44 years.