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3 years ago

Two waves are in phase if they are of the same ___________.

Physics

2 answers:

MariettaO [177]3 years ago

5 0

Answer:

frequency.

Explanation:

Two sound waves of the same frequency that are perfectly aligned have a phase difference of 0 and are said to be “in phase.” Two waves that are in phase add to produce a sound wave with an amplitude equal to the sum of the amplitudes of the two waves.

Fed [463]3 years ago

3 0

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An object is placed near a concave mirror having a radius of curvature of magnitude 60 cm. How far should you place the object f

Viefleur [7K]

Answer:

u = 18 cm

Explanation:

given,

radius of curvature = 60 cm

magnification of mirror = 2.5

distance of object = ?

R = 2 f

f = R/2

f = 60/2 = 30 cm

$m = -\dfrac{v}{u}$

$2.5 = -\dfrac{v}{u}$

v = -2.5 u

now,

Using mirror formula

$\dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}$

$\dfrac{1}{30} = \dfrac{1}{-2.5u} + \dfrac{1}{u}$

$\dfrac{1}{30} = \dfrac{0.6}{u}$

u = 0.6 x 30

u = 18 cm

distance of object be equal to u = 18 cm

6 0

3 years ago

An object is released from rest at time t = 0 and falls through the air, which exerts a resistive force such that the accelerati

rosijanka [135]

Answer:

A) $\frac{g}{b}(1-e^{-bt})$

Explanation:

Since a = g - bv,

We can substitute a = dv/dt into the equation.

Then, the equation will be like dv/dt = g - bv.

So we got first order differential equation.

As known, v = 0 at t = 0, and v = g/b at t = ∞.

Since $\frac{dv}{dt}= g - bv = b( \frac{g}{b} - v)$ ⇒ $\frac{dv}{ \frac{g}{b} - v}= bdt$

So take the integral of both side.

$- ln (\frac{g}{b} - v) = bt + C$

Since for t=0, v = 0 ⇒ $C =- ln (\frac{g}{b})$

$v = \frac{g}{b} + e^{-bt-ln(\frac{g}{b})} = \frac{g}{b}- \frac{g}{b}e^{-bt} = \frac{g}{b}(1-e^{-bt})$

5 0

3 years ago

The smallest shift you can reliably measure on the screen is about 0.2 grid units. This shift corresponds to the precision of po

creativ13 [48]

Answer:

The distance is $d = 1.5 *10^{15} \ km$

Explanation:

From the question we are told that

The smallest shift is $d = 0.2 \ grid \ units$

Generally a grid unit is $\frac{1}{10}$ of an arcsec

This implies that 0.2 grid unit is $k = \frac{0.2}{10} = 0.02 \ arc sec$

The maximum distance at which a star can be located and still have a measurable parallax is mathematically represented as

$d = \frac{1}{k}$

substituting values

$d = \frac{1}{0.02}$

$d = 50 \ parsec$

Note $1 \ parsec \ \to 3.26 \ light \ year \ \to 3.086*10^{13} \ km$

So $d = 50 * 3.08 *10^{13}$

$d = 1.5 *10^{15} \ km$

3 0

3 years ago

A certain bridge is 4,224 feet long. What constant rate, in miles per hour, must be maintained in order to walk across the bridg

Archy [21]

Answer:

4miles/hour

Explanation:

the solution for this question requires that the quantities are converted to the appropriate units as required by the question.

Rate in miles per hour = distance in miles / time in hour

to convert 12 minutes to hours; recall that 60 minutes make 1 hour

12 minutes to hour = 12/60 = 0.2hr

to convert 4224 feet to miles; recall 5280 feet is equivalent to 1 mile

4224 feet to miles = 4224/5280 = 0.8 miles

∴ rate = 0.8 / 0.2

rate = 4 miles per hour

the constant rate in miles per hour = 4 miles/hour

4 0

3 years ago

A tennis ball moving at a speed of 4 m/s, collides with a bowling ball at rest. The tennis ball bounces back in the direction op

Alex Ar [27]

Answer:

Both experienced the same magnitude impulse

Explanation:

This is because, the impulse force is internal to the system of both the tennis ball and the bowling ball. It is an action-reaction pair. So, the force exerted on the tennis ball by the bowling ball equals in magnitude to the force exerted by the tennis ball on the bowling ball although, they are in opposite directions. This, both experienced the same magnitude impulse.

3 0

3 years ago