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slavikrds [6]
3 years ago
13

A red racecar accelrates at a constant rate of 5 m/s2. How much time does it take to increase its speed from 50 m/s to 60 m/s?

Physics
1 answer:
natulia [17]3 years ago
7 0
A red racecar accelrates at a constant rate of 5 m/s2. How much time does it take to increase its speed from 50 m/s to 60 m/s?


A.17 s


B.0.058 s


C.0.25 s


D.2.0 s
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Two long, straight wires are separated by a distance of 32.2 cm. One wire carries a current of 2.75 A, the other carries a curre
Igoryamba

Answer:

a)\frac{F_1}{L}=1.95*10^-^5N

b)\frac{F_2}{L}=1.95*10^-^5N

Explanation:

From the question we are told that:

Distance between wires d=32.2

Wire 1 current I_1=2.75

Wire 2 current I_2=4.33

a)

Generally the equation for Force on l_1 due to I_2 is mathematically given by

F_1=I_1B_2L

Where

B_2=Magnetic field current by I_2

B_2=\frac{\mu *i_2}{2\pi d}

Therefore

F_1=I_1B_2L

F_1=I_1(\frac{\mu *i_2*l_1}{2\pi d})L

\frac{F_1}{L} =\frac{4*\pi*10^{-7}*2.75*4.33*100 }{2*\pi*12.2 }

\frac{F_1}{L}=1.95*10^-^5N

b)

Generally the equation for Force on I_2 due to I_1 is mathematically given by

F_2=I_2B_1L

Where

B_1=Magnetic field current by I_2

B_1=\frac{\mu *I_1}{2\pi d}

Therefore

\frac{F_2}{L} =I_2(\frac{\mu *I_1*I_2}{2\pi d})

\frac{F_2}{L}=1.95*10^-^5N

5 0
2 years ago
Is a mirrors surface transparent translucent or opaque how do you know.
Eva8 [605]
There are actually two different kinds of mirrors, and the answer is different
for each one.

-- Plain old everyday hand mirror, vanity mirror, bathroom mirror, makeup
mirror, etc.

Opaque, reflecting silver coating is on the back of the glass. 
Light from your tongue or your teeth flows to the front surface of the glass,
through the glass, out of the back surface of the glass, bounces off of the silver
coating on the back, reverses its direction, enters the back surface of the glass,
comes back through the glass again, leaves the front of the glass, goes into your
eyes, and you can see your teeth or your tongue.

Both surfaces of the glass, as well as the glass in between the surfaces, are
transparent.  The silver coating on the back is opaque.  I know that, because
when I look at the back of a mirror, I can't see any light coming through it. 
The coating on the back is also reflective ... a big part of the reason why
a mirror works.

-- Expensive mirrors used by astronomers and eye-doctors.
Known as "first surface" mirrors.

Opaque, reflecting silver coating is on the <em>front</em> of the glass. 
Light from your tongue or your teeth flows toward the front surface of the glass,
but never actually gets there.  It bounces off of the silver coating on the front of
the glass, reverses its direction, goes into your eyes, and you can see your teeth
or your tongue.

The glass is transparent, but that doesn't matter, because the light never reaches
the glass. It only goes as far as the opaque silver coating on the front, and is
reflected from there.

4 0
3 years ago
A cylinder contains 250 L of hydrogen gas (H2) at 0.0^∘Cand a pressure of 10.0 atm. How much energy is required to raise the tem
Over [174]

Answer:

The amount of energy needed to raise the temperature of the cylinder by 25 °C is 23.3 KJ of heat.

Explanation:

The step by step calculation can be found in the attachment below. Thank you.

8 0
2 years ago
A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10
sashaice [31]

Answer:

Time interval;Δt ≈ 37 seconds

Explanation:

We are given;

Angular deceleration;α = -1.6 rad/s²

Initial angular velocity;ω_i = 59 rad/s

Final angular velocity;ω_f = 0 rad/s

Now, the formula to calculate the acceleration would be gotten from;

α = Change in angular velocity/time interval

Thus; α = Δω/Δt = (ω_f - ω_i)/Δt

So, α = (ω_f - ω_i)/Δt

Making Δt the subject, we have;

Δt = (ω_f - ω_i)/α

Plugging in the relevant values to obtain;

Δt = (0 - 59)/(-1.6)

Δt = -59/-1.6

Δt = 36.875 seconds ≈ 37 seconds

6 0
3 years ago
Please help, thanks!
statuscvo [17]
Because it demonstrates the relationship between a body and the forces acting upon it, and its motion in response to those forces. [Hope that helps]
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3 years ago
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