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slavikrds [6]
3 years ago
13

A red racecar accelrates at a constant rate of 5 m/s2. How much time does it take to increase its speed from 50 m/s to 60 m/s?

Physics
1 answer:
natulia [17]3 years ago
7 0
A red racecar accelrates at a constant rate of 5 m/s2. How much time does it take to increase its speed from 50 m/s to 60 m/s?


A.17 s


B.0.058 s


C.0.25 s


D.2.0 s
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A copper cable needs to carry a current of 160 A with a power loss of only 2.0 W/m. What is the required radius of the copper ca
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Answer:

The radius of the cable is 0.0083 m or 8.3 mm.

Explanation:

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R_{cable} = \frac{\rho \times l}{a}    ....     (i)

where the resistivity of copper is \rho = 1.7 \times 10^{-8} \Omega.m , and l is the length of the wire which is considered to be 1m, and a is the cross sectional area of the wire in m^{2}.

From the formula of power we know that, P = I^2 R    ....    (ii)

Therefore 2 W/m  = (160)^2 \times R     ....     (iii)  

where  the resistance,R, actually means the resistance of the cable per meter.

Therefore R ( resistance of cable per meter)

= \frac{2}{160^2}  = 7.812 \times 10^{-5} ohms / meter.       ....    (iv)

Therefore from (i)

7.812 \times 10^{-5} = \frac{1.7 \times 10^{-8} \times 1}{a}  = \frac{1.7 \times 10^{-8} \times 1}{\pi r^{2} }       .....     (v)

where cross sectional area of the cable, a  = \pi r^2,

where r is the radius of the cable, and length of cable,l = 1m.

Therefore r  = \sqrt{\frac{ 1.7 \times 10^{-8}}{\pi \times 7.812 \times 10^{-5} } }  =  0.0083m = 8.3 mm

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The inductance of a closely packed coil of 560 turns is 8.9 mH. Calculate the magnetic flux through the coil when the current is
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