Answer:
V = 192 kV
Explanation:
Given that,
Charge, ![q=6.4\times 10^{-6}\ C](https://tex.z-dn.net/?f=q%3D6.4%5Ctimes%2010%5E%7B-6%7D%5C%20C)
Distance, r = 0.3 m
We need to find the electric potential at a distance of 0.3 m from a point charge. The formula for electric potential is given by :
![V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 6.4\times 10^{-6}}{0.3}\\\\V=192000\ V\\\\V=192\ kV](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7Bkq%7D%7Br%7D%5C%5C%5C%5CV%3D%5Cdfrac%7B9%5Ctimes%2010%5E9%5Ctimes%206.4%5Ctimes%2010%5E%7B-6%7D%7D%7B0.3%7D%5C%5C%5C%5CV%3D192000%5C%20V%5C%5C%5C%5CV%3D192%5C%20kV)
So, the required electric potential is 192 kV.
<span> One </span>volt<span> is </span>defined<span> as the difference in electric potential between two points of a conducting wire when an electric current of one ampere dissipates one watt of power between those points.</span>
Answer:Water Only
Explanation:
Given
vessel is insulated therefore no heat can be added or removed i.e. heat exchange is zero
If hot water at
is mixed with cold water at
then at equilibrium vessel contains only water and final temperature of water will be between
and ![T_2](https://tex.z-dn.net/?f=T_2)
Heat released by hot water is equal to heat gain by cold water .