1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Triss [41]
3 years ago
14

The figures below are rectangles. Which polynomial represents the area of the shaded region? HAVE ALL MY POINTS but answer truth

fully cause i have the answer choices

Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0

Answer:

7x - 1

Step-by-step explanation:

Area of the shaded region = area of the large rectangular - area of the small rectangle

Area of rectangle is given as l*w

Area of the large rectangle = l*w = (x + 5)(x - 1)

Expand

= x(x - 1) +5(x - 1)

= x^2 - x + 5x - 5

Area of large rectangle = x^2 + 4x - 5

Area of small rectangle = l*w = (x + 1)(x - 4)

= x(x - 4) +1(x - 4)

=  x^2 - 4x + x - 4

Area of small rectangle = =  x^2 - 3x - 4

Area of shaded region = (x^2 + 4x - 5) - (x^2 - 3x - 4)

= x^2 + 4x - 5 - x^2 + 3x + 4

Collect like terms

= x^2 - x^2 + 4x + 3x - 5 + 4

= 7x - 1

You might be interested in
An atom of silicon is approximately 0.00000000025 meters wide. How do you express that number in scientific notation? O 25 10-10
garik1379 [7]

Answer:

mohydty868788

Step-by-step explanation:

8 0
3 years ago
What is the GCF and LCM of -21 and 80? Please Help! Explanation Please! :) Will give brainliest! ASAP!
Lisa [10]

Answer:

GCF= 1

LCM= 1680

Step-by-step explanation:

GCF= Find the prime factorization of 21, 21 = 3 x 7

Find the prime factorization of 80, 80 = 2 x 2 x 2 x 2 x 5

Then multiply the prime factors both numbers have in common

LCM= multiply the two numbers together and ignore all negative signs

5 0
3 years ago
A job candidate at a large job fair can be classified as unacceptable, provisional, or acceptable. Based on past experience, a h
svp [43]

Answer:

chisquare = 31.667

degree of freedom = 2

Step-by-step explanation:

Formula for chisquare test =  (O-E)²/E

total number observations= 60 + 25 + 15 = 100                  

Estimated E,

80% x 100 = 80

15%x100 = 15

5% x 100 = 5

chisquare =

\frac{(60-80)^{2} }{80} +\frac{(25-15)^{2} }{15}+\frac{(15-5)^{2} }{5}\\

= 5 + 6.67 + 20

= 31.667

from the calculation above the value of the chisquare statistic = 31.67

the degree of freedom is the number of samples in the test  n - 1

= 3-1

= 2

I have solve this question also in a tabular form to aid understanding in the file i uploaded.

thank you and good luck!

4 0
3 years ago
Helppppppppppppppppppppppppppppppppppppppppppppp
jek_recluse [69]
You’re trying to find the better buy so you want to find out how much you’re paying per unit (in this case kg)

So you divide the price by the unit (kg)

And find the better buy by looking at which price is cheapest.

Your answer is the 7.48 kg bag


Hope this helps and good luck!!

8 0
2 years ago
A pair of shoes is on sale for 80% off the original price. The sale price is $60. What was the original price
ella [17]
I am not sure but it might be $12
6 0
3 years ago
Other questions:
  • Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest
    12·1 answer
  • I don’t understand need help
    5·2 answers
  • Solve The equation Pls i need this ASAP! <br><br> y + (–6) = –9
    14·2 answers
  • Please help asap!<br><br>the problem is in the picture
    7·1 answer
  • There are 154 players on 11 teams . How many players are on one team
    8·1 answer
  • (3x +2)<br> 2x<br> (x, sol<br> (2x+1001
    7·1 answer
  • Given the data: 136, 150, 119, 150, 125, 143.<br> Find the range.
    9·1 answer
  • PLEASE PLEASE HELP IGNORE MY ANSWERS
    15·1 answer
  • Identify the hypothesis of the statement.If AB is a segment, then it has two endpoints.
    9·1 answer
  • We choose a 4-digit number randomly. What is the probability that all its digits are even? help asap
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!