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NNADVOKAT [17]
4 years ago
7

ABCD is rectangle on a coordinate grid with side AB parallel to side CD. Side BC is perpendicular to AB. The slip of AB is 3/4.

what is the slope of BC?
Mathematics
1 answer:
dybincka [34]4 years ago
6 0

The slope of BC is \frac{-4}{3}

Step-by-step explanation:

Let us revise some notes about slopes of lines

  • If two lines are parallel, then their slopes are equal
  • If to lines are perpendicular, then the product of their slopes is -1, that means if the slope of one is m, then the slope of the other is \frac{-1}{m}

∵ ABCD is a rectangle

∵ AB // CD

∴ The slope of AB = the slope of CD

∵ BC ⊥ AB

∴ The slope of BC × the slope of AB = -1

∵ The slope of AB = \frac{3}{4}

- To find the slope of BC reciprocal the slope of AB and reverse its sign

∴ The slope of BC = \frac{-4}{3}

The slope of BC is \frac{-4}{3}

Learn more:

You can learn more about the slope in brainly.com/question/9801816

#LearnwithBrainly

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Step-by-step explanation:

Use trigonometry.

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3 years ago
Leonard made the 3-d shape below for an art project. He wants to paint it blue.
tia_tia [17]

Answer:

90 cm^{2} of blue paint

Step-by-step explanation:

From the given diagram, the sides have the same dimensions and the shape of a triangle.

Area of a triangle = \frac{1}{2} x base x height

Given that, the base of each side = 6 cm, and the height = 10 cm.

Then,

Area of each side of the shape = \frac{1}{2} x 6 x 10

                                              = 30 cm^{2}

Since Leonard wish to paint only the 3 sides and not the bottom part of the shape, the amount of paint required can be determined as;

3 x area of each side = 3 x 30

                                   = 90 cm^{2}

Leonard would need 90 cm^{2} of paint to paint the sides of the shape.

6 0
3 years ago
Una empresa exportadora de frutas vende dos variedades de frambuesas: estándar y de lujo. Una caja de freses estándar se vende e
aksik [14]

Answer:

83.33 cajas estándar de frambuesas y 51.67 cajas de lujo de frambuesas.

Step-by-step explanation:

Representemos el número de cajas como

A = caja estándar de frambuesas

B = caja de lujo de frambuesas

Caja estándar de frambuesas = $ 7 Caja de lujo de frambuesas = 10.

A + B = 135 ......... Ecuación 1

B = 135 - A

7A + 10B = 1100 ........... Ecuación 2

Sustituir

135 - A para B en la ecuación 2

7A + 10 (135 - A) = 1100

7A + 1350 -10A = 1100

7A - 10A = 1100-1350

-3A = - 250

A = 250/3

A = 83.33 cajas

Sustituye 83.33 por A en la ecuación 1

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83,33 + B = 135

B = 135 - 83.33 = 51.67 cajas

Por lo tanto, vendió,

83.33 cajas estándar de frambuesas y 51.67 cajas de lujo de frambuesas.

6 0
3 years ago
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