Question

An electron starts with a speed of 5.50×105 m/s . It moves in a region with an electric field. Some time later the electron has been brought to res What is the change in electric potential V in going from the initial to the final position? Make sure your sign is correct. Express your answer with the appropriate units.

Answer 1

Answer:

-0.8611796875 V

Explanation:

m = Mass of electron = $9.11\times 10^{-31}\ kg$

q = Charge of electron = $1.6\times 10^{-19}\ C$

v = Velocity of electron = $5.5\times 10^5\ m/s$

The potential difference is given by

$V=\dfrac{K_f}{e}-\dfrac{K_i}{e}\\\Rightarrow V=-\dfrac{\dfrac{1}{2}mv^2}{e}\\\Rightarrow V=-\dfrac{\dfrac{1}{2}\times 9.11\times 10^{-31}\times (5.5\times 10^5)^2}{1.6\times 10^{-19}}\\\Rightarrow V=-0.8611796875\ V$

The change in electric potential is -0.8611796875 V