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rodikova [14]
2 years ago
10

If velocity is positive, which would most likely yield a negative acceleration?

Physics
1 answer:
defon2 years ago
7 0

The correct answer for velocity if acceleration is opposite is:

* An initial velocity that is faster than a final velocity

The given parameters are acceleration and initial velocity, it is asked to find the final speed of the body

In kinematics, position, velocity, and acceleration are quantities that are related.

 The magnitude and direction of the acceleration are given by the resultant force on the body, in many cases the resultant force is constant in various time intervals, therefore the  is acceleration is constant in these intervals even though it may have a different value in each one.

The velocity of the body is defined by the change in position of the body in the unit of time, in the most common case of a system with constant acceleration the velocity is given by

      v_f = v₀ + a t

where v₀ and v_{f} are the initial and final velocities of the body, a is the acceleration and t is a time scalar: the bold letters indicate vectors.

If the velocity has a direction and the acceleration is contrary to the equation, we can see that the final velocity must decrease as time advances.  Therefore the correct statement is: O An initial velocity that is faster than a final velocity.

Learn more here: brainly.com/question/2136991

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Bryce, a mouse lover, keeps his four pet mice in a roomy cage, where they spend much of their spare time (when they are not slee
user100 [1]

Answer:

I₁ = (7.78 i ^ - 6.71 j ^) 10⁻³ J s ,  I₂ = (-12.5 i ^ -14.6 j ^) 10⁻³ J s ,  I₃ = (19.1i ^ + 18.6 j ^) 10⁻³ J s  and I₄ = (-9.14i ^ + 7.24 j ^) 10⁻³ J s

Explanation:

The impulse is equal to the variation of the moment, to apply this relationship to our case, we will assume that initially the mouse was at rest

    I = Δp = m v_{f} -m v₀

    I = m (v_{f}  -v₀)

Bold indicates vector quantities, let's calculate the momentum of each mouse in for the x and y axes

We recommend bringing all units to the SI system

Mouse 1.

It has a mass of 22.3 g = 22.3 10⁻³ kg, a final velocity of (v = 0.349 i ^ - 0.301 j ^) m / s with an initial velocity of zero

    Iₓ = m (v_{fx}  - v₀ₓ)

    Iₓ = 22.3 10⁻³ (0.349 -0)

    Iₓ = 7.78 10⁻³ J s

   I_{y} = m (v_{fy}  -v_{oy} )

   I_{y} = 22.3 10⁻³ (-0.301)

   I_{y} = -6.71 10⁻³ J s

   I₁ = (7.78 i ^ - 6.71 j ^) 10⁻³ J s

Mouse 2

Mass 17.9 g = 17.9 10⁻³ kg

Speed ​​(-0.699 i ^ - 0.815 j ^) m / s

    Iₓ = m (v_{fx}  - v₀ₓ)

    Iₓ = 17.9 10⁻³ (-0.699 -0)

    Iₓ = -12.5 10⁻³ J s

    I_{y} = 17.9 10⁻³ (-0.815 - 0)

    I_{y} = -14.6 10⁻³ J s

   I₂ = (-12.5 i ^ -14.6 j ^) 10⁻³ J s

Mouse 3

Mass 19.1 g = 19.1 10⁻³ kg

Speed ​​(0.745i ^ + 0.975 j ^) m / s

    Iₓ = 19.1 10⁻³ (0.745 -0)

    Iₓ = 14.2 10⁻³ J s

    I_{y} = 19.1 10⁻³(0.975 -0)

    I_{y} = 18.6 10⁻³ J s

    I₃ = (19.1i ^ + 18.6 j ^) 10⁻³ J s

Mouse 4

Mass 10.1 g = 10.1 10⁻³ kg

Speed ​​(-0.905i ^ + 0.717j ^) m / s

    Iₓ = 10.1 10⁻³ (-0.905 -0)

    Iₓ = -9.14 10⁻³ J s

    I_{y} = 10.1 10⁻³ (0.717 -0)

    I_{y} = 7.24 10⁻³ J s

   I₄ = (-9.14i ^ + 7.24 j ^) 10⁻³ J s

8 0
3 years ago
A man stands on top of a cliff and shouts.
satela [25.4K]

\small\bf \: let \: the \: distance \: of \: the \: man \: from \: the \: cliff \: be \: x

\small\bf \: thus \: time \: taken \: by \: sound \: to \: hit \: the \: cilff \: and \: return =  \frac{2x}{v}  = 1

\bf \to \: x =  \frac{320}{2} m = 160m

\small \bf \: thus \: the \: distance \: between \: the \: cliffs \:  = 160m \times 2 = 320m

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A car starts from rest and drives at 45 m/s in 20 s. how far did it travel
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Answer:

distance=speed×time.

45×20=900m.

6 0
3 years ago
Which of the following accurately shows how to calculate the weight of a 20kg object
forsale [732]
The answer to your question is "20kgx9.8m/s" because weight is the force an object is exerting on another object, and the formula used to calculate force is <em>Force = Mass * Acceleration</em>.
4 0
3 years ago
Read 2 more answers
Definition of continental polar
kipiarov [429]

Answer:

Continental polar (cP) or continental arctic (cA) air masses are cold, dry, and stable. These air masses originate over northern Canada and Alaska as a result of radiational cooling. Maritime polar (mP) air masses are cool, moist, and unstable.

Explanation:

8 0
3 years ago
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