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Korvikt [17]
3 years ago
14

A single-slit diffraction pattern is formed on a distant screen. Assuming the angles involved are small, by what factor will the

width of the central bright spot on the screen change if the slit width is doubled? A single-slit diffraction pattern is formed on a distant screen. Assuming the angles involved are small, by what factor will the width of the central bright spot on the screen change if the slit width is doubled? It will be cut in half. It will double. It will become eight times as large. It will be cut to one-quarter its original size. It will become four times as large.
Physics
1 answer:
Novay_Z [31]3 years ago
4 0

Answer:

It will be cut in half

Explanation:

The diffraction of a slit is given by the formula

a sin θ = m where

a = width of the slit,

λ = wavelength and

m = integer that determines the order of diffraction.

Next we divide both sides by a, we have

sin θ = m λ / a

Also, recall that

a’ = 2 a

Then we substitute in the previous equation

2asin θ' = m λ, if divide by 2a, we have

sin θ' = (m λ / 2a).

Now again, from the first equation, we said that sin θ = m λ / a, so we substitute

sin θ ’= sin θ / 2

Then we use trigonometry to find the width, we say

tan θ = y / L

Since the angle is small, we then have

tan θ = sin θ / cos θ

tan θ = sin θ, this then means that

sin θ = y / L

we will then substitute

y’ / L = y/L 1/2

y' = y / 2

this means that when the slit width is doubled the pattern width will then be halved

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Suppose an object is launched from a point 320 feet above the earth with an initial velocity of 128 ft/sec upward, and the only
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Answer:

(a)Therefore the highest altitude attained by the object is =576 ft .

(b)Therefore the object takes 6 sec to fall to the ground.

Explanation:

Initial velocity: Initial velocity is a velocity from which an object starts to move.

u is usually used for notation of initial notation.

Final velocity: Final velocity is a velocity of an object after certain second from starting.

The final velocity is denoted by v.

Acceleration: The difference of final velocity and initial velocity per unit time

The S.I unit of acceleration is m/s².

(a)

Given that u= 128 ft\sec and g = 32 ft/sec².

At highest point the velocity of the object is 0 i.e v=0

Since the displacement is opposite to the gravity.

Therefore acceleration( a)= -g = -32 ft/sec².

To find the time this to happen we use the following formula

v=u+at

Here v=0

⇒0=128+(-32) t

⇒32t=128

⇒t = 4 sec

To determine the height we use the following formula

s=ut+\frac{1}{2} at^2

\Rightarrow s= (128\times4)+\frac{1}{2}\times (-32) \times4^2

⇒s= 256 ft

Therefore the highest altitude attained by the object is =(320+256)ft=576 ft .

(b)

At the highest point the velocity of the object is 0.

so u=0. a=g= 32 ft/sec²  [ since the direction of gravity and the displacement are same] s= 576 ft

To determine the time to fall we use the following formula

s=ut+\frac{1}{2} at^2

\Rightarrow 576 = (0\times t)+\frac{1}{2} \times 32 \times t^2

\Rightarrow 16\times t^2=576

\Rightarrow t^2=\frac{576}{16}

\Rightarrow t^2=36

⇒t=6 sec

Therefore the object takes 6 sec to fall to the ground.

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____________loosens up your muscles and brings your heart rate up in a slow, steady way that’s better for your body.
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Answer:

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Artyom0805 [142]

Answer:

<h2>59.5 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

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From the question we have

force = 70 × 0.85

We have the final answer as

<h3>59.5 N</h3>

Hope this helps you

6 0
3 years ago
A particle is moving in a circle of diameter 5. calculate the distance covered and the displacement when it completes 3 revoluti
Mamont248 [21]

Total distance covered is 47.1 m whereas displacement is zero.

<h3>Calculation:</h3>

Given,

Diameter, d = 5 m

No. of revolutions = 3

Radius, r = 5/2 = 2.5 m

To find,

Distance =?

Displacement =?

Distance covered in one revolution = 2πr

                                                           

Put the values in this,

Distance = 2 × 3.14 × 2.5

               = 15.7 m

Total distance covered in 3 revolution = 3 × 31.4

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Displacement is the change in the position of the object or the distance between the initial and final position.

After 3 revolutions the particle comes back to its initial position. Therefore, the displacement is zero.

Hence, the total distance covered in 3 resolutions is 47.1 m whereas displacement is zero.

Learn more about distance and displacement here:

brainly.com/question/3243551

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1 year ago
Hi:) why do metals have free electrons? anyone able to explain the conduction part as well? Thanks!
Karo-lina-s [1.5K]

Metals have free electrons due to the bonding in metallic substances.

In a metal there are strong attractive forces between the nuclei and the valance electrons.

Positively charged metal nuclei form a lattice (a cube like structure) each metal atom provides one or more valance electrons <u>that are free to move throughout the lattice</u> The electrons are attracted to the positively charged nuclei but not one individual nuclei, this is called non-directional bonding since it occurs in all directions.

Now all metals are conductive becuase of the free to move (delocalised) electrons. Since the valance electrons are free to move throughout the lattice they are able to carry a charge. (Ionic solids cannot since the ionic solids form a tightly packed lattice with cations and anions which have no free moving electrons, electrons have to be able to move to carry a charge)

<u />

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3 years ago
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