Hey there, Your answer wold be 1.36 newtons rounded to 1.4 newton. This is how!
force = k (q1 * q2) / r^2
<span>= (9.0 × 10^9 Nm^2/C^2) [(7.1 × 10^-6 C) (6.9 × 10^-6 C)] / (5.7 × 10^-1 m)^2
</span>
<span>= [ 9.0 × 7.1 × 6.9 / (5.7)^2 ] × 10^-1 N
</span>
<span>= 13.6 × 10^-1 N
</span>
<span>= 1.36 N
</span>
ANSWER-1.4
HOPE I HELPED!!!!!!!!!!
For finding the orbital speed of the satellite we can say that the centripetal force for the circular motion of satellite is provided by the gravitational force of earth
so here we can say


now we will have

now here we will say that orbital speed of the satellite is inversely depends on the orbital radius
<em>So here if orbital speed is half then as per above relation we can say that orbital distance will become four times</em>
<em>Also we can say that if orbital speed is double then orbital distance will become one fourth of initial distance.</em>
Given,
The momentum of the object A before the collision, p₁ =80 Ns
The momentum of the object B before the collision, p₂=-30 Ns
Given that the objects stick together after the collision.
From the law of conservation of momentum, the total momentum of a system should always remain the same. Thus the total momentum of the objects before the collision must be equal to the total momentum of the objects after the collision.
Thus,

Where p is the total momentum of the system at any instant of time.
On substituting the known values,

Therefore the total momentum of the system is 50 Ns
Thus the momentum of the object AB after the collision is 50 Ns