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Pie
3 years ago
14

Uma criança anda em uma pista circular de raio 100m, gastando 20 minutos para percorrer metade da pista. Indique o deslocamento

da criança.
Physics
1 answer:
Alinara [238K]3 years ago
5 0

Answer: 200m

Explanation:

This can be translated to:

A child walks on a circular track with a radius of 100m, spending 20 minutes to cover half the track. Indicate the child's displacement.

Ok, we want to know the displacement, which is equal to the difference between the initial position and the final position.

if the kid starts at any point of the circular track, we know that he covers half the track, so he actually covers a semicircle.

This means that we can connect the initial position and the final position with the diameter of the circle.

(The diameter is two times the radius).

Then the distance between the final position and the initial position (the total displacement) is equal to two times the radius:

Displacement = 2*100m = 200m

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Answer:net force:20N, accel. :4m/s2

Explanation:

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3 years ago
Two metal balls have charges of 7.1 × 10-6 coulombs and 6.9 × 10-6 coulombs. They are 5.7 × 10-1 meters apart. What is the force
Zinaida [17]
Hey there, Your answer wold be 1.36 newtons rounded to 1.4 newton. This is how!

force = k (q1 * q2) / r^2 

<span>= (9.0 × 10^9 Nm^2/C^2) [(7.1 × 10^-6 C) (6.9 × 10^-6 C)] / (5.7 × 10^-1 m)^2 
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<span>= [ 9.0 × 7.1 × 6.9 / (5.7)^2 ] × 10^-1 N 
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<span>= 13.6 × 10^-1 N 
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ANSWER-1.4 


HOPE I HELPED!!!!!!!!!!
6 0
3 years ago
Read 2 more answers
What would happen to a satellite if it’s orbit speed was reduced by half? Also how about if it doubled?
weeeeeb [17]

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now we will have

v = \sqrt{\frac{GM}{r}}

now here we will say that orbital speed of the satellite is inversely depends on the orbital radius

<em>So here if orbital speed is half then as per above relation we can say that orbital distance will become four times</em>

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8. Object A has a momentum of 80 Ns and collides and sticks to object B which has a momentum of -30 Ns. What is the momentum of
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Given,

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The momentum of the object B before the collision, p₂=-30 Ns

Given that the objects stick together after the collision.

From the law of conservation of momentum, the total momentum of a system should always remain the same. Thus the total momentum of the objects before the collision must be equal to the total momentum of the objects after the collision.

Thus,

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On substituting the known values,

\begin{gathered} p=80-30 \\ =50\text{ Ns} \end{gathered}

Therefore the total momentum of the system is 50 Ns

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