Ask question

Ask question

All categories

3 years ago

11

Sasha did an experiment to study the solubility of two substances. She poured 100 mL of water at 20 °C into each of two beakers

labeled A and B. She put 50 g of Substance A in the beaker labeled A and 50 g of Substance B in the beaker labeled B. The solution in both beakers was stirred for 1 minute. The amount of substance left undissolved in the beakers was weighed. The experiment was repeated for different temperatures of water and the observations were recorded as shown. (8 points)
Experimental Observations
Substance Mass of Undissolved Substance at Different Temperatures (gram)
20 °C 40 °C 60 °C 80 °C
A 12 11 9 8
B 45 40 34 31
Part 1: Which substance has a higher solubility?
Part 2: Explain your answer for Part 1.

1 answer:

chubhunter [2.5K]3 years ago

4 0

Answer:

b is the higher solubility then A

You might be interested in

Suzette had prepared the graph below to add to her lab

Charra [1.4K]

Answer:

A title

Explanation:

Because this is middle school.

4 0

3 years ago

Read 2 more answers

What is the perfect amount of sunlight needed on a planet.

gogolik [260]

Answer:

20 years Light.

Explanation:

There's no practical explanation just math's.

6 0

2 years ago

In the rocket, what is the equal and opposite reaction?

netineya [11]

Answer:

see below

Explanation:

Gases flying out at high velocity out the back

rocket flying forward

7 0

2 years ago

A charged capacitor is connected to an ideal inductor. At time t = 0, the charge on the capacitor is equal to 6.00 μC. At time t

Len [333]

Answer:

$4.71\times 10^{-3}A$

Explanation:

$Q_{max}$ = Maximum charge stored by capacitor = 6 μC = 6 x 10⁻⁶ C

$t$ = time taken for charge on the capacitor to become zero = 2 ms = 2 x 10⁻³ s

Time period is given as

$T = 4t$

$T = 4(2\times 10^{-3})$

$T = 8\times 10^{-3} s$

Angular frequency is given as

$w = \frac{2\pi }{T}$

$w = \frac{2(3.14) }{8\times 10^{-3}}$

$w$ =785 rad/s

Charge at any time is given as

$Q(t) = Q_{max}Coswt$

Taking derivative both side relative to "t"

$\frac{\mathrm{d}Q(t) }{\mathrm{d} t} = \frac{\mathrm{d}(Q_{max}Coswt) }{\mathrm{d} t}$

$i(t)= -Q_{max} w Sinwt$

Amplitude of the current is given as

$i_{max}= Q_{max} w$

$i_{max}= (6\times 10^{-6}) (785)$

$i_{max}= 4.71\times 10^{-3}A$

8 0

3 years ago

Two acrobats flying through the air grab and hold onto each other in midair as part of a circus act.One acrobat has a mass of 60

earnstyle [38]

Answer:

1.36m/s

Explanation:

We are given that

Mass of one acrobat, $m_1=60 kg$

Mass of another acrobat, $m_2=50 kg$

$v_2=-3 m/s$

$v_1=5 m/s$

We have to find their velocity immediately after they grab onto each other.

The collision between two acrobat is inelastic

According to law of conservation of momentum

$m_1v_1+m_2v_2=(m_1+m_2)V$

Substitute the values

$60\times 5+50(-3)=(60+50)V$

$300-150=110V$

$V=\frac{300-150}{110}=1.36m/s$

4 0

3 years ago