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2 years ago

What happens to the wavelength as the frequency of a whale noise changes from 200hz to 300hz

Physics

1 answer:

rewona [7]2 years ago

4 0

Answer:

When there is an increase in the frequency of sound waves, the wavelength decreases.

Explanation:

Given data,

The frequency of the whale changes from 200 Hz to 300 Hz

The formula for frequency and wavelength is,

λ = v/f

Where v is the velocity of the sound waves in water (1531 m/s)

The wavelength at 200 Hz is,

λ = 1531/200

= 7.655 m

The wavelength at 300 Hz is,

λ = 1531/300

= 5.1 m

Hence, when there is an increase in the frequency of sound waves, the wavelength decreases.

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A car moving at a speed of 10 m/s enters a Q. highway and accelerates at 4 m/s2. How fast will the car be moving after it accele

geniusboy [140]

Initial velocity=u=10m/s
Final velocity=v
Acceleration=a=4m/s^2
Distance=s=60m

According to third equation of kinematics

$\\ \rm\rightarrowtail v^2=u^2+2as$

$\\ \rm\rightarrowtail v^2=10^2+2(4)(60)$

$\\ \rm\rightarrowtail v^2=100+480$

$\\ \rm\rightarrowtail v^2=580$

$\\ \rm\rightarrowtail v\approx 24m/s$

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2 years ago

A wire 1.0 m long experiences a magnetic force of 0.50 N due to a

NNADVOKAT [17]

Answer:

11.50

thenks me later

hehehehe how old are you

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2 years ago

(a) Calculate the magnitude of the gravitational force exerted by Mars on a 80 kg human standing on the surface of Mars. (The ma

andrew11 [14]

Answer:

a) $F=1.044\times 10^9\ N$

b) $F'=1.044\times 10^9\ N$

c) $F_p=1.0672\times10^{-7}\ N$

d) Treat the humans as though they were points or uniform-density spheres.

Explanation:

Given:

mass of Mars, $M=6.4\times 10^{23}\ kg$

radius of the Mars, $r=3.4\times 10^{6}\ m$

mass of human, $m=80\ kg$

Gravitation force exerted by the Mars on the human body:

$F=G.\frac{M.m}{r^2}$

where:

$G=6.67 \times 10^{-11}\ m^3.kg^{-1}.s^{-2}$ = gravitational constant

$F=6.67\times10^{-11}\times \frac{6.4\times 10^{23}\times 80}{(3.4\times 10^{6})^2}$

$F=1.044\times 10^9\ N$

The magnitude of the gravitational force exerted by the human on Mars is equal to the force by the Mars on human.

$F'=F$

$F'=1.044\times 10^9\ N$

When a similar person of the same mass is standing at a distance of 4 meters:

$F_p=6.67\times10^{-11}\times \frac{80\times 80}{4}$

$F_p=1.0672\times10^{-7}\ N$

The gravitational constant is a universal value and it remains constant in the Universe and does not depends on the size of the mass.

Yes, we have to treat Mars as spherically symmetric so that its center of mass is at its geometric center.

Yes, we also have to ignore the effect of sun, but as asked in the question we have to calculate the gravitational force only due to one body on another specific body which does not brings sun into picture of the consideration.

4 0

2 years ago

According to the law of refraction, light passing from air into a piece of glass at an angle of 30 degrees will cause the light

pantera1 [17]

Answer:

bend toward the normal line

Explanation:

When light passes from a less dense to a more dense substance, (for example passing from air into water), the light is refracted (or bent) towards the normal. In your question the light is moving from rarer to denser medium

4 0

3 years ago

What is the kinetic energy of a 1.40 kg discus with a speed of 22.5 m/s?

Oksana_A [137]

Kinetic energy = (1/2) (mass) (speed)²

   = (1/2) (1.4 kg) (22.5 m/s)²

   = (0.7 kg) (506.25 m²/s² )

   = 354.375 kg-m²/s² = 354.375 joules .

This is just the kinetic energy associated with a 1.4-kg glob of
mass sailing through space at 22.5 m/s. In the case of a frisbee,
it's also spinning, and there's some additional kinetic energy stored
in the spin.

8 0

2 years ago