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iris [78.8K]
3 years ago
14

What happens to the wavelength as the frequency of a whale noise changes from 200hz to 300hz

Physics
1 answer:
rewona [7]3 years ago
4 0

Answer:

When there is an increase in the frequency of sound waves, the wavelength decreases.

Explanation:

Given data,

The frequency of the whale changes from 200 Hz to 300 Hz

The formula for frequency and wavelength is,

                             λ = v/f

Where v is the velocity of the sound waves in water (1531 m/s)

The wavelength at 200 Hz is,

                             λ = 1531/200

                                = 7.655 m

The wavelength at 300 Hz is,

                             λ = 1531/300

                                = 5.1 m

Hence, when there is an increase in the frequency of sound waves, the wavelength decreases.

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The particles ejected from the sun during a coronal mass ejection is called
ipn [44]

Answer:

Plasma

Explanation:

A Coronal Mass Ejection (CME) is an outburst of energy that occurs near the outer part of the sun's atmosphere which causes a production of plasma along with a magnetic field.

The outermost part of the sun's atmosphere is called the Solar Corona Although difficult to see, the corona can be seen during a total solar eclipse.

Plasma from CME are clouds of magnetized electrically charged particles which the solar wind causes to travel at a speed of 1.6 million km/hr.

7 0
3 years ago
Plates move apart at ____ boundaries.
Keith_Richards [23]
<span>The correct answer is C. divergent. Divergent boundaries are something like lines found between two tectonic plates. These constructive boundaries, or extensional boundaries, are formed and exist between two tectonic plates that move away from each other. Convergent would thus be where they meet. This is all according to the tectonic theory.</span>
5 0
3 years ago
Read 2 more answers
Please help me with my science homework
Viktor [21]
For the "what is this investigation about", you could pick
the shape of the Earth, the size of the Earth, how the Sun
generates its energy, the distance to the Moon, why the 
sky is blue ... things like that.  There are millions uvum.

Trustworthy sources of information:
-- an Encyclopedia
-- a library book that's all about the subject of the investigation
-- a magazine that's all about exactly the subject of the investigation
-- a TV program that's ALL ABOUT the subject of the investigation
-- a teacher who teaches the subject of the investigation
-- a high school student whose hobby is the subject of the investigation
-- an adult whose hobby is the subject of the investigation
-- an adult whose JOB is the subject of the investigation
-- a high school student who got a very good grade in a course
where the subject of the investigation was taught 
-- a college student who is studying the same subject as the investigation 

UN-trustworthy sources of information:
(This doesn't mean that they're always wrong.  It means that
they can tell you something, and you just can't be sure of
whether it's right or wrong.)
-- some sources listed on Google
-- some YouTube videos
-- other students in your class
-- other students at your school 
-- your next-door neighbor (unless he's on the 'trustworthy' list above)
-- a newspaper article
-- a TV news item, or a TV program that's NOT all about the subject
-- a public opinion poll; (just because everybody thinks so
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-- your sister's friend's hairdresser's grocer's mother-in-law
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5 0
4 years ago
What is the mass of a 2 kg object on the Earth and on the moon?
zubka84 [21]

Answer:

Same

Explanation:

Mass is the quantity of matter in a certain object.

WHEREVER you take a 2kg object, the mass will remain 2kg. All that changes is the Weight ..Weight the force which the centre of a Planet uses to pull everything towards itself.

On earth, it is 9.81 whereas on the Moon it is 1.6

7 0
3 years ago
A block of mass 0.221 kg is placed on top of a light, vertical spring of force constant 5365 N/m and pushed downward so that the
Anvisha [2.4K]

Answer:

The maximum height above the point of release is 11.653 m.

Explanation:

Given that,

Mass of block = 0.221 kg

Spring constant k = 5365 N/m

Distance x = 0.097 m

We need to calculate the height

Using stored energy in spring

U=\dfrac{1}{2}kx^2...(I)

Using gravitational potential energy

U' =mgh....(II)

Using energy of conservation

E_{i}=E_{f}

U_{i}+U'_{i}=U_{f}+U'_{f}

\dfrac{1}{2}kx^2+0=0+mgh

h=\dfrac{kx^2}{2mg}

Where, k = spring constant

m = mass of the block

x = distance

g = acceleration due to gravity

Put the value in the equation

h=\dfrac{5365\times(0.097)^2}{2\times0.221\times9.8}

h=11.653\ m

Hence, The maximum height above the point of release is 11.653 m.

3 0
3 years ago
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