Ask question

Ask question

All categories

3 years ago

7

A boy pushes a 5 kg box across the floor with a force of 25 N. There is a 5 N frictional force opposing him. What is the net for

ce and the acceleration of the box?

1 answer:

11Alexandr11 [23.1K]3 years ago

8 0

Answer:net force:20N, accel. :4m/s2

Explanation:

You might be interested in

(a) Calculate the buoyant force on a 2.00-L helium balloon.

iragen [17]

Answer:

0.0239364 N

0.0057879 N

Explanation:

$\rho$ = Density of the gas

g = Acceleration due to gravity = 9.81 m/s²

V = Volume

Mass of rubber = 1.5 g

Buoyant force is given by

$F_b=\rho gV\\\Rightarrow F_b=1.22\times 9.81\times 2\times 10^{-3}\\\Rightarrow F_b=0.0239364\ N$

The buoyant force is 0.0239364 N

Net vertical force is given by

$F_n=F_b-W_{He}-W_{r}\\\Rightarrow F_n=0.0239364-0.175\times 2\times 10^{-3}\times 9.81-1.5\times 10^{-3}\times 9.81\\\Rightarrow F_n=0.0057879\ N$

The net vertical force is 0.0057879 N

6 0

4 years ago

The _____ of a mechanical wave is a direct measure of its energy.

KiRa [710]

I think it's amplitude

6 0

4 years ago

If the distance between a neutral atom and a point charge is quadrupled, by what factor does the force on the atom by the point

IgorLugansk [536]

New force or Old Force

8 0

4 years ago

Plzzzzzzz help me<br> 15 pt for 1st 10 for 2nd

maks197457 [2]

Mass is the right answer

8 0

3 years ago

Read 2 more answers

A particle starts from rest and has an acceleration function 5 − 10t m/s2 . (a) What is the velocity function? (b) What is the p

frez [133]

Explanation:

It is given that,

A particle starts from rest and has an acceleration function as :

$a(t)=(5-10t)\ m/s^2$

(a) Since, $a=\dfrac{dv}{dt}$

v = velocity

$dv=a.dt$

$v=\int(a.dt)$

$v=\int(5-10t)(dt)$

$v=5t-\dfrac{10t^2}{2}=5t-5t^2$

(b) $v=\dfrac{dx}{dt}$

x = position

$x=\int v.dt$

$x=\int (5t-5t^2)dt$

$x=\dfrac{5}{2}t^2-\dfrac{5}{3}t^3$

(c) Velocity function is given by :

$v=5t-5t^2$

$5t-5t^2=0$

t = 1 seconds

So, at t = 1 second the velocity of the particle is zero.

7 0

3 years ago