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3 years ago

6

Name three elements that are good conductors of heat

1 answer:

Vera_Pavlovna [14]3 years ago

7 0

Copper, gold and silver are three of them.

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During both the vernal equinox and _____________, there is an equal amount of night and day.

choli [55]

During both the Vernal Equinox and Autumnal equinox, there is an equal amount of night and day
Vernal Equinox marks the beginning of Spring and Autumnal Equinox marks the beginning of Fall

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3 years ago

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If the heart becomes damaged or weakened, how will this affect the body’s systems?

mr Goodwill [35]

Answer:

As your heart works harder, it becomes weaker and the damage increases. Your body gets less oxygen, and you might notice symptoms like shortness of breath, swelling in your legs, and fluid buildup. Your body tries to keep the blood it has to supply your heart and brain.

Explanation:

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3 years ago

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What’s is the movement of one object around another

allsm [11]

Answer:

revolution

Explanation:

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3 years ago

Shawn and his bike have a total mass of

Trava [24]

Answer:

Shawn's kinetic energy is 61.45 J.

Explanation:

Given;

Mass of the system is, $m=52.3\ kg$

Displacement of the bike is, $d=1.6\ km=1.6\times 1000=1600\ m$

Time taken is, $t=17.4\ min=17.4\times 60=1044\ s$

Let the constant velocity be $v$ .

For constant velocity, magnitude of velocity is given as distance by time.

Therefore, $v=\frac{d}{t}=\frac{1600}{1044}=1.533\ m/s$

Now, kinetic energy of a body is given as:

$KE=\frac{1}{2}mv^2$

Here, $m=52.3\ kg,\ v=1.533\ m/s$

$\therefore KE=\frac{1}{2}\times 52.3\times (1.533)^2\\KE=0.5\times 52.3\times 2.35\\KE=61.45\ J$

Therefore, Shawn's kinetic energy is 61.45 J.

3 0

3 years ago

A 1500-kg car locks its brakes and skids to a stop on a slippery horizontal road, leaving skid marks that are 15 m long. How muc

Harman [31]

Answer:

$E=88200\ J$

Explanation:

Given:

mass of car, $m=1500\ kg$

distance of skidding after the application of brakes, $d=15\ m$

coefficient of kinetic friction, $\mu_k=0.4$

<u>So, the energy dissipated during the skidding of car:</u>

<em>Frictional force:</em>

$f=\mu_k.N$

where N = normal reaction by ground on the car

$f=0.4\ties 1500\times 9.8$

$f=5880\ N$

<em>Now from the work-energy equivalence:</em>

$E=f.d$

$E=5880\times 15$

$E=88200\ J$ is the dissipated energy.

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3 years ago