Answer:
400 W/m^2 and 31℃
Explanation:
The output heat flux q"= 20 W/m^2 (geven)
The output heat flux from.the wall to the air by convection
q"conv = h(ts - t∞)
q"conv = 20(50-30) = 400 W/m^2
Therefor, this case is unsteady and the wall temperature changes with time till the energy balance exist.
ENERGY BALANCE
The input energy must be equal to the output energy for steady state condition. If not the state will be unstaidy or transient.
2. Its noticed that the output heat flux is not that the I put heat flux, therefore the wall tempers will be decreased till the output heat flux is reduced to the value of the given input heat flux
T steady = T∞ +q"/h
= 30 + 20/20 = 31℃
A. It is a compound made of oxygen and carbon
It is powered by the Earth's rotation and the moon gives a little boost.
Answer:
43.16°
Explanation:
λ = Wavelength = 1.4×10⁻¹⁰ m
θ₁ = 20°
n can be any integer
d = distance between the two slits
Since for the first bright fringe, n₁ = 1
n₂ = 2 for second order line
The relation between the distance of the slits and the angle through which it is passed is:
dsinθ=nλ
As d and λ are constant
![\frac{n_1\lambda}{sin \theta_1}=\frac{n_2\lambda}{sin \theta_2}\\\Rightarrow \frac{1}{sin20}=\frac{2}{sin\theta_2}\\\Rightarrow sin\theta_2=\frac{2}{\frac{1}{sin20}}\\\Rightarrow \theta_2=sin^{-1}{\frac{2}{\frac{1}{sin20}}}\\\Rightarrow \theta_2=43.16^{\circ}](https://tex.z-dn.net/?f=%5Cfrac%7Bn_1%5Clambda%7D%7Bsin%20%5Ctheta_1%7D%3D%5Cfrac%7Bn_2%5Clambda%7D%7Bsin%20%5Ctheta_2%7D%5C%5C%5CRightarrow%20%5Cfrac%7B1%7D%7Bsin20%7D%3D%5Cfrac%7B2%7D%7Bsin%5Ctheta_2%7D%5C%5C%5CRightarrow%20sin%5Ctheta_2%3D%5Cfrac%7B2%7D%7B%5Cfrac%7B1%7D%7Bsin20%7D%7D%5C%5C%5CRightarrow%20%5Ctheta_2%3Dsin%5E%7B-1%7D%7B%5Cfrac%7B2%7D%7B%5Cfrac%7B1%7D%7Bsin20%7D%7D%7D%5C%5C%5CRightarrow%20%5Ctheta_2%3D43.16%5E%7B%5Ccirc%7D)
∴ Angle by which the second order line appear is 43.16°
The horizontal component of the velocity of the ball is calculated by multiplying the speed by the cosine of the given angle.
x-component of speed = (31 m/s)(cos 35°)
= 25.39 m/s
Thus, the horizontal velocity component of the ball is 25.39 m/s.