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Anna007 [38]
3 years ago
8

A fighter jet travels 10km at an angle of 30 degrees. He then turns sharply and flies 25 km at an angle of 75 degrees. What is t

he fighter jets displacement
Physics
1 answer:
FrozenT [24]3 years ago
7 0

Answer:

24.4 km

Explanation:

First displacement , d' = 10 km at an angle 30°

second displacement, d'' = 25 km at an angle 75° with the previous one

Write the displacements in the vector form

\overrightarrow{d'} =10 ( Cos 30 \widehat{i} + Sin 30 \widehat{j})

\overrightarrow{d'} =8.66\widehat{i} + 5\widehat{j}

\overrightarrow{d''} =25 ( - Cos 45 \widehat{i} + Sin 45 \widehat{j})

\overrightarrow{d''} =-17.68\widehat{i} + 17.68\widehat{j}

The net displacement is given by

\overrightarrow{d}= \overrightarrow{d'}+ \overrightarrow{d''}

\overrightarrow{d}= - 9.02 \widehat{i} + 22.68 \widehat{j}

the magnitude of the displacement is given by

d=\sqrt{9.02^{2}+22.68^{2}}

d = 24.4 km

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Answer:

Cp= 0.44 J/g.C

This is heat capacity of metal.

Explanation:

From energy conservation

Heat lost by metal = Heat gain by water +Heat gain by  calorimeter

Because here temperature of metal is high that is why it loose the heat.The temperature of water and  calorimeter is low that is why they gain the heat.

final temperature is T= 30.5 C

We know that sensible heat transfer given as

Q= m Cp ΔT

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ΔT=Temperature difference

By putting the values

55 x Cp ( 99.5 - 30.5) = 40 x 4.184 ( 30.5- 21 ) + 10 x ( 30.5 - 21)

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4 0
3 years ago
The average radius of Mars is 3,397 km. If Mars completes one rotation in 24.6 hours, what is the tangential speed of objects on
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Answer: First, we determine the circumference of the Mars by the equation below.  

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Substituting the known values,

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6 0
2 years ago
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Which sound wave-object interaction is used by animals in echolocation?
tekilochka [14]
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5 0
3 years ago
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When the mass of the bottle is 0.125 kg, the KE is______ kg m2/s2.
DiKsa [7]
Answers are:
(1) KE = 1 kg m^2/s^2
(2) KE = 2 kg m^2/s^2
(3) KE = 3 kg m^2/s^2
(4) KE = 4 kg m^2/s^2


Explanation:

(1) Given mass = 0.125 kg
speed = 4 m/s

Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
Hence:
KE = (1/2) * 0.125 * (16)
KE = 1 kg m^2/s^2

(2) Given mass = 0.250 kg
speed = 4 m/s

Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
Hence:
KE = (1/2) * 0.250 * (16)
KE = 2 kg m^2/s^2

(3) Given mass = 0.375 kg
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Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
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KE = 3 kg m^2/s^2

(4) Given mass = 0.500 kg
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Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
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KE = (1/2) * 0.5 * (16)
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