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Anna007 [38]
3 years ago
8

A fighter jet travels 10km at an angle of 30 degrees. He then turns sharply and flies 25 km at an angle of 75 degrees. What is t

he fighter jets displacement
Physics
1 answer:
FrozenT [24]3 years ago
7 0

Answer:

24.4 km

Explanation:

First displacement , d' = 10 km at an angle 30°

second displacement, d'' = 25 km at an angle 75° with the previous one

Write the displacements in the vector form

\overrightarrow{d'} =10 ( Cos 30 \widehat{i} + Sin 30 \widehat{j})

\overrightarrow{d'} =8.66\widehat{i} + 5\widehat{j}

\overrightarrow{d''} =25 ( - Cos 45 \widehat{i} + Sin 45 \widehat{j})

\overrightarrow{d''} =-17.68\widehat{i} + 17.68\widehat{j}

The net displacement is given by

\overrightarrow{d}= \overrightarrow{d'}+ \overrightarrow{d''}

\overrightarrow{d}= - 9.02 \widehat{i} + 22.68 \widehat{j}

the magnitude of the displacement is given by

d=\sqrt{9.02^{2}+22.68^{2}}

d = 24.4 km

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A car starts from 0 m along a road and accelerates at 0.5 m/s^2 to the right. A second car starts from 1000 m along the road and
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Answer:

e) 31.6 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Equation of motion

s=ut+\frac{1}{2}at^2\\\Rightarrow s_1=0\times t+\frac{1}{2}\times 0.5\times t^2\\\Rightarrow s_1=\frac{1}{2}0.5t^2\ m

s=ut+\frac{1}{2}at^2\\\Rightarrow s_2=0\times t+\frac{1}{2}\times 0.5\times t^2\\\Rightarrow s_2=\frac{1}{2}1.5t^2\ m

s_1+s_2=1000

\\\Rightarrow 1000=\frac{1}{2}0.5t^2+\frac{1}{2}1.5t^2\\\Rightarrow 1000=\frac{0.5t^2+1.5t^2}{2}\\\Rightarrow 1000=\frac{2t^2}{2}\\\Rightarrow 1000=t^2\\\Rightarrow t=\sqrt{1000}\\\Rightarrow t=31.6\ s

Time taken by the cars to meet 31.6 seconds.

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3 years ago
A ray of light is incident on a plane mirror at an angle of 30 degree state the angle of reflection?​
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Answer:

30°

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∠i = ∠r

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∠r will also be 30°

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A 1.11 kg piece of aluminum at 78.3 c is put into a glass with 0.210 kg of water at 15.0
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M = mass of aluminium = 1.11 kg

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T_{ai} = initial temperature of aluminium = 78.3 c

m = mass of water = 0.210 kg

c_{w} = specific heat of water = 4186

T_{wi} = initial temperature of water = 15 c

T = final equilibrium temperature = ?

using conservation of heat

Heat lost by aluminium = heat gained by water

M c_{a} (T_{ai} - T) = m c_{w} (T - T_{wi} )

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What current flow (I) is associated with an input voltage of 5.0V and resistors R1 = 1.5 kiloohms and R2 = 0.5 kiloohms? Calcula
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Answer:

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Explanation:

given data

voltage = 5 V

resistors R1 = 1.5 kilo ohms

resistors R2 = 0.5 kilo ohms

to given data

current flow

solution

current flow in series is express as here

current = voltage / resistor    .................1

put here all value  in equation 1

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so current = 2.50 mA

and

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put here all value in equation  2

current = 5 / (1/ (1/1.5 + 1/0.5))

current = 5 / 0.37

so current = 13.31 mA

5 0
3 years ago
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