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Fed [463]
3 years ago
6

What is latent heat? A. energy released or absorbed to change the kinetic energy of a substance B. energy released or absorbed t

o change the pressure of a substance C. energy released or absorbed to change the temperature of a substance D. energy released or absorbed to change the phase of a substance
Physics
2 answers:
kkurt [141]3 years ago
6 0

the heat required to convert a solid into a liquid or vapor, or a liquid into a vapor, without change of temperature. hope this helps

Dmitrij [34]3 years ago
5 0

The correct choice is

D. energy released or absorbed to change the phase of a substance.

By definition, latent heat is the amount of heat required by an object to change from one state to another. for example : heat required for 1 g of ice at 0 °C converts to water at 0 °C is 334 J.  heat required for 1 g of water at 100 °C to vaporize is 2230 J.

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What do electric forces between charges depend on?
bonufazy [111]

Electrostatic forces between charges depend on the product of
the sizes of the charges, and the distance between them.

We should also mention the item about whether the charges are
both the same sign or opposite signs.  That determines whether
the forces will pull them together or push them apart, which is a
pretty significant item.

6 0
4 years ago
Read 2 more answers
Two stones resembling diamonds are suspected of being fakes. To determine if the stones might be real, the mass and volume of ea
dimaraw [331]

Answer:

stone A is diamond.

Explanation:

given,

Volume of the two stone =  0.15 cm³

Mass of stone A = 0.52 g

Mass of stone B = 0.42 g

Density of the diamond =  3.5 g/cm³

So, to find which stone is gold we have to calculate the density of both the stone.

We know,

density\density = \dfrac{mass}{volume}

density of stone A

\rho_A = \dfrac{0.52}{0.15}

\rho_A = 3.467\ g/cm^3

density of stone B.

\rho_B = \dfrac{0.42}{0.15}

\rho_B = 2.8\ g/cm^3

Hence, the density of the stone A is the equal to Diamond then stone A is diamond.

6 0
3 years ago
You walk east for 10m then turn north 15m what is your displacementm
Doss [256]
25m north east hope this helps
5 0
3 years ago
An object is released from rest high above the surface of the earth. When it has fallen halfway to the surface, its kinetic ener
aksik [14]

Answer:

There will be an increase in the kinetic energy

Explanation:

A falling object converts the gravitational potential energy to the kinetic energy. The potential energy is then converted to kinetic energy followed by the conversation:

E_{p} = E_{k}

where Ep and Ek are potential and kinetic energies respectively.

This potential energy is then converted to kinetic energy. Halfway, the kinetic energy is equal to KE1.

However, the kinetic energy is given by the equation:

KE = \frac{1}{2}mv^{2}

As the velocity increases, the kinetic energy increases. Hence KE2 will be greater than KE1

4 0
4 years ago
Gravitational attraction depends on the mass of the objects as well as their distance. The gravitational force between objects i
shepuryov [24]
<h2>Answer: Gravitational attraction will be the same</h2>

According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:

F=G\frac{m_{1}m_{2}}{r^2}    (1)

Where:

F is the module of the force exerted between both bodies

G is the universal gravitation constant.

m_{1} and m_{2} are the masses of both bodies.

r is the distance between both bodies

Now, if we double both masses and the distance also doubles, this means:

m_{1} and m_{2} will be now 2m_{1} and 2m_{2}

r will be now 2r

Let's rewrite the equation (1) with this new values:

F=G\frac{(2m_{1})(2m_{2})}{(2r)^2}    (2)

Solving and simplifying:

F=4G\frac{m_{1}2m_{2}}{4r^2}    

F=G\frac{m_{1}m_{2}}{r^2}     (3)

As we can see, equation (3) is the same as equation (1).

So, if the masses both double and the distance also doubles the <u>Gravitational attraction between both masses will remain the same.</u>

7 0
3 years ago
Read 2 more answers
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