Answer:
c) 387g
Explanation:
Water;
Mass = 250g
Specific heat = 4.184
Initial Temp, T1 = 25 + 273 = 298K
Final Temp, T2 = 35 + 273 = 308K
Heat = ?
H = mc(T2 - T1)
H = 250 * 4.184 (308 - 298)
H = 10460 J
Iron;
Initial Temp, T2 = 95 + 273 = 368K (Upon converting to kelvin temperature)
Mass = ?
Final Temp, T1 = 35 + 273 = 308
Heat = 10460 (Heat lost by iron is qual to heat gained by water)
Specific heat = 0.45
H = mc(T2-T1)
M = 10460 / [0.45 (308 - 368)]
M = 10460 / 27
M = 387g
Answer:
281s
Explanation:
Given parameters:
Speed of the scooter = 1.45min per mile
Fuel economy of engine = 85miles per gallon
Quantity of fuel = 145mL
Unknown:
Time of travel with the volume of fuel given = ?
Solution:
To solve this problem, we need to find the distance the fuel will last.
Rate of fuel consumption by the engine = 85miles per gallon
Convert 145mL to gallons;
3785.41mL = 1 gallon
145mL will therefore give
= 0.038gallons
So;
Distance covered = 85miles per gallon x 0.038gallons = 3.23miles
From;
Rate of travel =
Time = rate of travel x distance = 1.45 minutes per mile x 3.23miles
Time = 4.7min
1 min = 60s
4.7min = 4.7 x 60 = 281s
Answer:
When you have the feeling of danger and you either don't want to face it or you want to face it.
Explanation: