The mass of 3.0 x 10²³ molecules of nitrogen gas is 13.95 g.
<h3>Mass of the Nitrogen gas</h3>
The mass of one mole of Nitrogen gas is 28 g/mol.
<h3>Number of atoms </h3>
The number of atoms in one mole of Nitrogen gas is 6.022 x 10²³ molecules.
The mass of Nitrogen gas in the given number of molecules is calculated as follows;
6.022 x 10²³ --------------------- 28 g/mol
3.0 x 10²³ ----------------------------- ?
Thus, the mass of 3.0 x 10²³ molecules of nitrogen gas is 13.95 g.
Learn more about mass of gas molecules here: brainly.com/question/11641158
Answer:
0.005 mol
Explanation:
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
w = given mass of Gold = 1.05 g ,
m = molecular mass of Gold = 197 g/mol
<u>Hence , moles can be calculated as -</u>
n = w / m
= 1.05 g / 197 g/mol = 0.005 mol
Answer:
oxidation, synthesis, polymerization
Explanation: I took the test
Oxidation of D -Ribose in presence of hypobromous acid gives D-Ribonic acid
Answer:
More reactants will be produced
Explanation:
Le Chatelier's principle; adding additional product or reactant will move the equilibrium left or right to compensate and come back to equilibrium
By adding more product to your system at equilibrium, the equilibrium will shift towards reactants, more reactants will be produced
