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vredina [299]
2 years ago
8

A substance is a base if it has a pH value greater than___PLEASE ANSWER ASAP ​

Chemistry
1 answer:
WINSTONCH [101]2 years ago
8 0

Answer:

A substance is basic or alkaline if it's pH is greater than 7.0.

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Hunds Rule

Explanation:

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Anthony's homework assignment is to demonstrate that an orange has already undergone a chemical change. Which of the following
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100 ml of a 0.300 m solution of agno3 reacts with 100 ml of a 0.300 m solution of hcl in a coffee-cup calorimeter and the temper
Olin [163]

Answer:

100 ml of a 0.300 m solution of agno3 reacts with 100 ml of a 0.300 m solution of hcl in a coffee-cup calorimeter and the temperature rises from 21.80 °c to 23.20 °c. Assuming the density and specific heat of the resulting solution is 1.00 g/ml and 4.18 j/g ∙ °c respectfully, what is the ΔH°rxn?

39.013 kJ/mol.

Explanation:

AgNO3(aq) + HCl(aq) --------------> AgCl(s) + HNO3(aq)

We can calculate the amount of heat (Q) released from the solution using the relation:

Q = m.c.ΔT,

Where, Q is the amount of heat released from the solution (Q = ??? J).

m is the mass of the solution (m of the solution = density of the solution x volume of the solution = (1.0 g/mL)(200 mL) = 200 g.

c is the specific heat capacity of the solution (c = 4.18 J/g∙°C).

ΔT is the difference in the T (ΔT = final temperature - initial temperature = 23.20 °C - 21.80 °C = 1.4 °C).

∴ Q = m.c.ΔT = (200 g)(4.18 J/g∙°C)(1.4 °C) = 1170.4 J.

∵ ΔH°rxn = Qrxn/(no. of moles of AgNO₃).

Molarity (M) is defined as the no. of moles of solute dissolved in a 1.0 L of the solution.

M = (no. of moles of AgNO₃)/(Volume of the solution (L)).

∴ no. of moles of AgNO₃

               = (M)(Volume of the solution (L))

               = (0.3 M)(0.1 L) = 0.03 mol.

∴ ΔH°rxn

           = Qrxn/(no. of moles of AgNO₃)

            = (1170.4 J)/(0.03 mol)

            = 39013.33 J/mol

           = 39.013 kJ/mol.

7 0
3 years ago
The enthalpy of fusion of methanol (CH3OH) is 3.16 kJ/mol. How much heat would be absorbed or released upon freezing 25.6 grams
Verdich [7]

Answer:

There is  2.52 kJ of energy released (option 4)

Explanation:

Step 1: Data given

The enthalpy of fusion of methanol (CH3OH) is 3.16 kJ/mol

Mass of methanol = 25.6 grams

Molar mass of methanol = 32.04 g/mol

Step 2: Calculate moles of methanol

Moles methanol = mass methanol / molar mass methanol

Moles methanol = 25.6 grams / 32.04 g/mol

Moles methanol = 0.799 moles

Step 3: Calculate energy transfer

Energy  transfer = moles * enthalpy of fusion

Energy = 0.799 moles * 3.16 kJ/mol

Energy = 2.52 kJ released

There is  2.52 kJ of energy released

6 0
3 years ago
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