Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.

Multiply both sides by 100.


Divide both sides by 50.


The amount invested at 7% is
.
The amount invested at 8% is

The amount invested at 9% is

Thus, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
Answer:
g(x) = -6 - 3x
f(x) = X^6
Step-by-step explanation:
Answer:
these are two answers i got
-14=
-5=
Answer:
8cm²
Step by step explanation:
A= ½×4cm×4cm
A= ½×16cm²
A= 8cm²
Answer:69
Step-by-step explanation:
69•2= 138
69-11=58
58•3=174
174+138=312