Answer: apparent weighlessness.
Explanation:
1) Balance of forces on a person falling:
i) To answer this question we will deal with the assumption of non-drag force (abscence of air).
ii) When a person is dropped, and there is not air resistance, the only force acting on the person's body is the Earth's gravitational attraction (downward), which is the responsible for the gravitational acceleration (around 9.8 m/s²).
iii) Under that sceneraio, there is not normal force acting on the person (the normal force is the force that the floor or a chair exerts on a body to balance the gravitational force when the body is on it).
2) This is, the person does not feel a pressure upward, which is he/she does not feel the weight: freefalling is a situation of apparent weigthlessness.
3) True weightlessness is when the object is in a place where there exists not grativational acceleration: for example a point between two planes where the grativational forces are equal in magnitude but opposing in direction and so they cancel each other.
Therefore, you conclude that, assuming no air resistance, a person in this ride experiencing apparent weightlessness.
The units for G must be ![[N][m^2][kg^{-2}]](https://tex.z-dn.net/?f=%5BN%5D%5Bm%5E2%5D%5Bkg%5E%7B-2%7D%5D)
Explanation:
The magnitude of the gravitational force between two objects is given by:

where
F is the force
G is the gravitational constant
are the masses of the two objects
is the separation between the objects
We know that:
- The units of F are Newtons (N)
- The units of
are kilograms (kg) - The units of
are metres (m)
So, we can rewrite the equation in terms of G, to find its units:
![G=\frac{Fr^2}{m_1 m_2}=\frac{[N][m]^2}{[kg][kg]}=[N][m^2][kg^{-2}]](https://tex.z-dn.net/?f=G%3D%5Cfrac%7BFr%5E2%7D%7Bm_1%20m_2%7D%3D%5Cfrac%7B%5BN%5D%5Bm%5D%5E2%7D%7B%5Bkg%5D%5Bkg%5D%7D%3D%5BN%5D%5Bm%5E2%5D%5Bkg%5E%7B-2%7D%5D)
Learn more about gravitational force:
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Explanation:
(10) Mass of a soccer player, m = 0.42 kg
Initial speed, u = 0
Final speed, v = 32.5 m/s
Time, t = 0.21 s
We need to find the force that sends soccer ball towards the goal.
Force, F = ma

So, 65 N of force soccer ball sends towards the goal.
(11) Mass of the satellite, m = 72,000 kg
Initial speed, u = 0 m/s
Final speed, v = 0.63 m/s
Time, t = 1296 s
We need to find the force is exerted by the rocket on the satellite.
Force, F = ma

So, 35 N of the force is exerted by the rocket on the satellite.
Hence, this is the required solution.