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Fynjy0 [20]
3 years ago
6

n object is undergoing uniform circular motion. Which of the following is/are true? I. The object is moving at constant velocity

. II. The object is moving at constant speed. III. The object is accelerating.
Physics
1 answer:
Igoryamba3 years ago
8 0

Explanation:

When an object is moving in a circular path, the motion of the object is called uniform circular motion. The object moves under the action of centripetal acceleration. It is given by :

a=\dfrac{v^2}{r}

r is the radius of circular path

v is the speed of the object

In uniform circular motion, the object moves with constant speed. Also, the velocity of the object keeps on changing because it changes direction at every instant of time. Also, the object is accelerating due to change in velocity.

So, the correct options are (b) and (c).

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balls a, with a mass of 20 kg, is moving to the right at 20 m/s. At what velocity should Ball B, with a mass of 40 kg, move so t
Leya [2.2K]
In that case, their momentum must be equal. 
So, m1v1 = m2v2
20 * 20 = 40 * v2
v2 = 400 / 40
v2 = 10

In short, Your Answer would be: 10 m/s

Hope this helps!
3 0
3 years ago
How dose an atom change if all of its electrons are removed
Anni [7]

Answer:

When all the electrons are removed from an atom, it becomes something as a positively charged particles also known as alpha particles.

<u>Explanation: </u>

The bare nucleus which is positively charged help in scattering experiments as it has high penetrating powers. <em>An atom is made up of electrons, protons and neutrons. We need huge energy to separate the electrons from their parent atom, still making it separated brings you a particle with a positive charge and only mass having high penetrating power. </em>

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3 years ago
Peristalsis is the action caused by contractions of muscles in this structure in the digestive system...
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Answer:

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8 0
2 years ago
A car traveling at 50 m/s comes to a stop in 5 seconds. What is the<br> acceleration of this car?
Alexandra [31]

Answer:10

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4 0
2 years ago
A student at another university repeats the experiment you did in lab. Her target ball is 0.860 m above the floor when it is in
dexar [7]

Answer:

K = 0.076 J

Explanation:

The height of the target, h = 0.860  m

The mass of the steel ball, m = 0.0120 kg

Distance moved, d = 1.50 m

We need to find the kinetic energy (in joules) of the target ball just after it is struck. Let t is the time taken by the ball to reach the ground.

h=ut+\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}}

Put all the values,

t=\sqrt{\dfrac{2\times 0.860 }{9.8}} \\\\=0.418\ s

The velocity of the ball is :

v=\dfrac{1.5}{0.418}\\\\= $$3.58\ m/s

The kinetic energy of the ball is :

K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 0.0120\times 3.58^2\\\\=0.076\ J

So, the required kinetic energy is 0.076 J.

6 0
3 years ago
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