Answer:
Slope is -2
Step-by-step explanation:
Answer:
y = mx + b is slope-intercept form of the linear equation.
y - y1 = m(x - x1) is point-slope form of the linear equation.
Ax + By = C (A ≥ 0) is standard form of the linear equation.
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....
1
y – 5 = —— (x + 1)
3
1 1
y = —— x + —— + 5
3 3
1 16
(1) y = —— x + ——
3 3
Step-by-step explanation:
First, write it as an equation
2.50+3x=5.05
Next, subtract 2.50 from both sides
2.50-2.50+3x=5.05-2.50
3x=2.55
Divide 3 on both sides
3x/3=2.55/3
x=0.85
The cost of a bag of chips is 0.85
hope i helped :D
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )
<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))
<em>z</em> = (-3 - 3<em>i </em>) / 2
Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have
arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>
arg(<em>z</em>) = arctan(1) - <em>π</em>
arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>
arg(<em>z</em>) = -3<em>π</em>/4
where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.
