Question

Hey there can you please help me posted picture of question

Answer 1

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = 12
a = coefficient of squared term = 4
c = constant term = 9

Using the values, we get:

$x= \frac{-12+- \sqrt{144-4(4)(9)} }{2(4)} \\ \\ x= \frac{-12+-0}{8} \\ \\ x= \frac{-3}{2}$

So, the correct answer to this question is option B