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Temka [501]
3 years ago
15

Pls help I need dis for a good grade

Mathematics
2 answers:
love history [14]3 years ago
5 0

111) 5:4

112) 3.6

113) -4

114) 0.3 units down, 0.4 units to the left

Degger [83]3 years ago
4 0

111.) ratio of M:N is 6:5


112.) 3.6


113.) -3


114.) -0.7 probably? :p

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How do i factorize x2+14x+49
Fed [463]

Answer:

(x + 7) (x + 7)

Step-by-step explanation:

What's the square root of x^2?

That's x

What's the square root of 49

That's 7

And what makes 14?

7 + 7 = 14

So therefore the answer is (x + 7) (x + 7)

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A wallet is originally $11.00. With a 40% discount, what is the sales price?
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$6.60

Step-by-step explanation:

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I need help with this
MaRussiya [10]

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number one is 3 Step-by-step explanation:

number 2

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What is 90-45-12. Plzzz
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A company establishes a fund of 120 from which it wants to pay an amount,C, to any of its 20 employees who achieve a high-perfor
Leno4ka [110]

Answer:

C=120/2=60

Step by step Explanation'

To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.

For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.

Determine the maximum value of C, then the maximum value that C can have is 120/n

Let us represent X as the number of employees with high performance with a binomial distribution of

P =0.02( since the percentage of chance of achieving a high performance level is 2%)

n = 20 ( number of employees who achieve a high performance level)

The probability of X= 0 can be calculated

P( X= 0) = 0.98^n

P(X=0)=0.98^20

P(X=0)=0.668

P(X=1)=0.02*20*0.98^19

P(X=1)=0.272

P(X=2)=0.02^2*20*0.98^18

P(X=2)=0.053

Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)

BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,

Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2

then the maximum value that C can have is 120/n

C=120/2=60

7 0
3 years ago
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