So (95/9)x2x60 Cal used in (1/9)x60 mile run in 2 hr or 120 min
95/9= about 10.5 cal/min
1 cal= 4.2J/S
(10.5 x 4.2)/60= 0.735 watts
Let's split these two situations up.
Linda
Linda deposits $1,800 into an account that pays 7.5% interest, compounded.
The equation:
1,800× 1.075^x=y
Let's put in 10 for x.
1.075^10= 2.06103156 × 1,800= 3,709.85681≈ 3,710
Anna
Anna deposits $4,000 into an account that pays 5% interest, compounded.
The equation:
4,000× 1.05^x=y
Let's put in 10 for x.
1.05×10= 1.62889463×4,000= 6515.57852= 6516
A) Linda's account: $3,710
Anna's account: $6,516
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
