Question

Identify AC rounded to the nearest tenth. HELP ASAP!!

Answer 1

Answer:

AC = 11.7

Step-by-step explanation:

Use sine:

$sine=\dfrac{opposite}{hypotenuse}$

We have

$opposite=8\\hypotenuse=AC\\\alpha=43^o\\\\\sin43^o\approx0.682$

Substitute:

$\dfrac{8}{AC}=0.682$

$\dfrac{8}{AC}=\dfrac{682}{1,000}$                cross multiply

$682AC=8,000$                 divide both sides by 682

$AC=\dfrac{8,000}{682}$

$AC\approx11.7$