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sergey [27]
3 years ago
10

If a probability distribution is 5/12, 1/12, 1/4, x, what is the value of x?

Mathematics
1 answer:
babunello [35]3 years ago
3 0

Answer:

Correct option: A

Step-by-step explanation:

The properties of a probability distribution are:

  1. 0 < P (x = x) < 1.
  2. ∑ P (X = x) = 1.

The second property implies that the sum of all the probabilities of a random variable is 1.

Use this property to determine the value of <em>x</em> as follows:

\sum P(X=k)=\frac{5}{12}+\frac{1}{12}+\frac{1}{4}+x

                 1=\frac{5+1+3+12x}{12}

                 1=\frac{9+12x}{12}

               12=9+12x\\

             12x=12-9

             12x=3

                 x=\frac{3}{12}

                 x=\frac{1}{4}

Thus, the missing probability value is \frac{1}{4}.

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alina1380 [7]
The amount of time Jill spent to do her homework 
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Which means, the amount of times Jack needed to do his is 
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7 0
3 years ago
For some reason it is not 72
asambeis [7]

Answer:

Maybe the Answer is 504

Step-by-step explanation:

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7 0
2 years ago
Darren wanted to see how contagious yawning can be. To better understand this, he conducted a social experiment in which he yawn
denis23 [38]

Answer:

10.5 minutes

Step-by-step explanation:

Thinking about the problem

The modeling function is of the form P(t)=A⋅Bf(t), where B=4B=4B, equals, 4 and f(t)=\dfrac{t}{10.5}f(t)=

10.5

t

​

f, left parenthesis, t, right parenthesis, equals, start fraction, t, divided by, 10, point, 5, end fraction.

Note that each time f(t)f(t)f, left parenthesis, t, right parenthesis increases by 111, the quantity is multiplied by B=4B=4B, equals, 4.

Therefore, we need to find the ttt-interval over which f(t)f(t)f, left parenthesis, t, right parenthesis increases by 111.

Hint #22 / 3

Finding the appropriate unit interval

fff is a linear function whose slope is \dfrac{1}{10.5}

10.5

1

​

start fraction, 1, divided by, 10, point, 5, end fraction.

This means that whenever ttt increases by \Delta tΔtdelta, t, f(t)f(t)f, left parenthesis, t, right parenthesis increases by \dfrac{\Delta t}{10.5}

10.5

Δt

​

start fraction, delta, t, divided by, 10, point, 5, end fraction.

Therefore, for f(t)f(t)f, left parenthesis, t, right parenthesis to increase by 111, we need \Delta t=10.5Δt=10.5delta, t, equals, 10, point, 5. In other words, the ttt-interval we are looking for is 10.510.510, point, 5 minutes.

Hint #33 / 3

Summary

The number of people who yawned quadruples every 10.510.510, point, 5 minutes.

7 0
3 years ago
What is the equation for the linear model in the scatter plot obtained by choosing the two points closest to the line?
HACTEHA [7]

Answer:

Option C is the answer.

Step-by-step explanation:

To find the equation of the straight line equation i.e, we must be given with the two points \left (x_{1},y_{1} \right ) and \left (x_{2},y_{2}\right )

Since from the graph the two points closest to the line are\left ( 10,36 \right ) and \left ( 22,12 \right ).

Equation of line with two points closest to the line :

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where m is the slope.

First we find the slope(m)=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}  

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on simplify we get,  m=-2.

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Apply distributive property on right hand side, we get

y-36=-2\cdot x+20

Adding both sides by 36, we get

y=-2x+20+36

y=-2x+56.

The equation for the linear  model in the scatter plot obtained by the two closest point \left ( 10,36 \right ) and \left ( 22,12 \right ) closest to the line is,

y=-2x+56










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Step-by-step explanation:

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