Number of rooms can be wired by electrician is approximately 3
<em><u>Solution:</u></em>
Given that electrician needs
rolls of electrical wire to wire each room in a house
To find: number of rooms can he wire with
rolls of wire
From given information,
Rolls of wire needed for 1 room = ![3\frac{1}{4} = \frac{4 \times 3 + 1}{4} = \frac{13}{4}](https://tex.z-dn.net/?f=3%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cfrac%7B4%20%5Ctimes%203%20%2B%201%7D%7B4%7D%20%3D%20%5Cfrac%7B13%7D%7B4%7D)
Total rolls of wire = ![9\frac{1}{4} = \frac{4 \times 9 + 1}{4} = \frac{37}{4}](https://tex.z-dn.net/?f=9%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cfrac%7B4%20%5Ctimes%209%20%2B%201%7D%7B4%7D%20%3D%20%5Cfrac%7B37%7D%7B4%7D)
<em><u>So number of rooms can be wired:</u></em>
![\text{ number of rooms }=\frac{\text{ total rolls of wire}}{\text{ wire needed for 1 room}}](https://tex.z-dn.net/?f=%5Ctext%7B%20number%20of%20rooms%20%7D%3D%5Cfrac%7B%5Ctext%7B%20total%20rolls%20of%20wire%7D%7D%7B%5Ctext%7B%20wire%20needed%20for%201%20room%7D%7D)
![\text{ number of rooms } = \frac{\frac{37}{4}}{\frac{13}{4}} = \frac{37}{4} \times \frac{4}{13} = \frac{37}{13}](https://tex.z-dn.net/?f=%5Ctext%7B%20number%20of%20rooms%20%7D%20%3D%20%5Cfrac%7B%5Cfrac%7B37%7D%7B4%7D%7D%7B%5Cfrac%7B13%7D%7B4%7D%7D%20%3D%20%5Cfrac%7B37%7D%7B4%7D%20%5Ctimes%20%5Cfrac%7B4%7D%7B13%7D%20%3D%20%5Cfrac%7B37%7D%7B13%7D)
![\rightarrow\frac{37}{13} = 2.84 \approx 3](https://tex.z-dn.net/?f=%5Crightarrow%5Cfrac%7B37%7D%7B13%7D%20%3D%202.84%20%5Capprox%203)
Thus number of rooms can be wired is
or approximately 3 rooms
3! = (3*2*1) = 6 outcomes
Answer:
It's +2
Step-by-step explanation:
As the positive occurs on the right side of the negatives in the number line so if we keep extending on the right side so we get +2
Answer:
D. sin J = Cos L
Step-by-step explanation:
LK = √219² - 178² = 127.58
sin J = <u>LK/LJ</u> =127.58/219 = 0.58
Cos L = <u>Lk/LJ</u> = 0.58
sin L = 178/219 = 0.81
Cos J = 178/219 = 0.81
Tan J = 127.58/178 = 0.72
tan L = 178/127.58 = 1.40
It would be (x−9)(x+4)<span>
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