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Darya [45]
3 years ago
14

The density of a certain type of paint is 1.2 grams per cubic centimeter. A garage door that is 3 meters tall and 7 meters wide

is to be painted with a 1-millimeter-thick coat of paint (on the outside only). What is the mass (in grams) of the paint that will be needed to paint the door?
Mathematics
1 answer:
Naily [24]3 years ago
5 0
We know that
density=mass/volume
solve for mass
mass=density*volume

step 1
find the area of the garage door in cm²<span>
Area=300*700------> 210000 cm</span>²

step 2
find the volume of the paint
Volume=area*thick
thick=1 mm-----> 0.1 cm
Volume=210000*0.1-----> 21000 cm³

step 3
find the mass
mass=density*volume
density=1.2 g/cm³
volume=21000 cm³
mass=1.2*21000-----> 25200 grams

the answer is
25200 grams
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irga5000 [103]

Answer:

360

Step-by-step explanation:

To calculate the number of different combinations of 2 different flavours, 1 topping, and 1 cone, we are going to use the rule of multiplication:

             6          *        5             *           4           *          3             = 360

      1st flavour           2nd flavour  topping              cone

Because first, we have 6 possible options for the flavour, then we only have 5 possible options for the 2nd flavour. Then, we have 4 options for the topping and finally, we have 3 options for the cone.

It means that there are 360 different combinations of two different flavours, one topping, and one cone are possible

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2 years ago
The maroon team and the orange team played a game of football. The maroon team scored 20 points and the orange team scored 6 poi
Dafna1 [17]

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20/6 or 10/3

Step-by-step explanation:

5 0
2 years ago
I need number 4 pls help
Inga [223]

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3 0
2 years ago
Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 42-m-42-m squar
oee [108]

The area enclosed by the figure is 4533.48 square meters.

<u>Step-by-step explanation:</u>

Side length of the square = 42m

The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.

Radius of the semicircle = 21m

Area of the square = 42 x 42 = 1764 square meters

Area of 1 semicircle = π(21 x 21) /2

= (3.14) (441) /2

= 1384.74/2

= 692.37 square meters

Area of 4 semicircle = 4 x 692.37

= 2769.48 square meters

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The area enclosed by the figure is 4533.48 square meters.

7 0
2 years ago
A farmer wants to fence in a rectangular field that encloses 3600 square feet. One side of the field is along a river and does n
andriy [413]

Answer:

C(x) = \$3.50(\frac{x^2+7200}{x})

Step-by-step explanation:

Data provided in the question:

Area of the field = 3600 square feet

Fencing charges = $3.50 per foot

Let the side along the river be 'x' feet and the other side of the 'B'

now,

Area of rectangle = Bx = 3600 square feet

or

B = \frac{3600}{x} feet

and total length to be fenced = x + 2B

therefore,

Total cost of fencing = Fencing charges × total length to be fenced

or

Total cost of fencing = $3.50 × ( x + 2B )

substituting the value of B from (1)

Total cost of fencing, C(x) = \$3.50(x+2\times\frac{3600}{x})

or

C(x) = \$3.50(\frac{x^2+7200}{x})

4 0
3 years ago
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