What is the shape of the cross-section taken perpendicular to the base of a cone?
2 answers:
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(X-3)^2+5=14
Step 1: simplify both sides of the equation
X^2-6x+14=14
Step 2: subtract 14 from both sides
X^2-6x+14-14=14-14
X^2-6x=0
For this equation: a=1, b=-6,c=0
1x^2+-6x+0=0
Step 3: Use quadratic formula with a=1, b=-6, c=0
The answer is x=6 or x=0
Step 1: simplify both sides of the equation
X^2-6x+14=14
Step 2: subtract 14 from both sides
X^2-6x+14-14=14-14
X^2-6x=0
For this equation: a=1, b=-6,c=0
1x^2+-6x+0=0
Step 3: Use quadratic formula with a=1, b=-6, c=0
The answer is x=6 or x=0