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Dominik [7]
3 years ago
14

If the Titan lake froze, how would the change in kinetic energy attect the speed of the more

Chemistry
1 answer:
Annette [7]3 years ago
4 0

Answer:

Explanation:bye reducing the energy in the footages

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Use the periodic table to calculate the molar mass of each compound below. Give your answer to the correct number of significant
agasfer [191]
From the periodic table you get the atomic masses of each element.

These are the values that I have in my periodic table (use those numbers of your periodic table if your teache gave you a specific one)

Na: 23 g/mol
O: 16 g/mol
H: 1 g/mol
C: 12 g/mol
Ca: 40 g/mol
S: 32 g/mol
Mg: 24 g/mol
P: 31 g/mol

Now I will do some examples and you do the others:

1) NaOH: 1 atom of Na * 23 g/mol + 1 atom of O * 16 g/mol + 1 atom of H * 1 g/mol

=> 1*23g/mol + 1*16g/mol + 1*1g/mol = 40 g/mol

2) H2O

=> 2 atoms of H * 1 g/mol + 1 atom of O * 16 g/mol = 2*1g/mol + 1*16g/mol = 18 g/mol

3) Glucose: C6H12O6

6*12 g/mol + 12 * 1g/mol + 6*16 g/mol = 72g/mol + 12g/mol + 96 g/mol = 180 g/mol

4) CaSO4:

1*40 g/mol + 1*32g/mol + 4*16g/mol = 136 g/mol

Now you only have to do the last one by your own.


7 0
4 years ago
Read 2 more answers
Identify the oxidizing agent in the reaction: Sn(s) + 2H+(aq) → Sn2+(aq) + H2(g) Sn2+ H2 H+ Sn
MrRa [10]

Answer:

H⁺(aq)

Explanation:

Let's consider the following redox reaction.

Sn(s) + 2 H⁺(aq) → Sn²⁺(aq) + H₂(g)

We can identify both half-reactions.

Oxidation: Sn(s) → Sn²⁺(aq) + 2 e⁻

Reduction: 2 H⁺(aq) + 2 e⁻ → H₂(g)

Sn(s) undergoes oxidation so it is the reducing agent, while H⁺(aq) undergoes reduction so it is the oxidizing agent.

8 0
3 years ago
Calculate the molar concentration of the Cl⁻ ions in 0.87 M MgCl2(aq).
Fed [463]
The compound MgCl2(aq) is ionic which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MgCl2 that dissolves.
MgCl2(s) --> Mg+(aq) + 2 Cl⁻(aq)
            [Cl⁻] = 0.87 mol MgCl2/1L × 2 mol Cl⁻ / 1 mol MgCl2 = 1.7 M
The answer to this question is [Cl⁻] = 1.7 M
8 0
3 years ago
Phosphorus has three electrons in its 3p sublevel and sulfur has four. Phosphorus should have the lower ionization energy but it
Nadya [2.5K]

Answer:

B

Explanation:

First of all it is important to know that a half filled orbital is particularly stable. In phosphorus all the electrons occur singly in the 3p sublevel minimizing inter electronic repulsion hence it is more difficult to remove an electron from this energetically stable arrangement. In sulphur, electrons are paired in one of the 3p orbitals thereby lowering the energy of that level due to instability caused by interelectronic repulsion between two electrons in the same orbital.

8 0
3 years ago
H 2(g)+I 2(g)→2 H I(g)
dlinn [17]

Answer:

The images for the 3 sub-questions have been presented in the first, second and third attached image to this solution.

Explanation:

The reaction for the reaction between Hydrogen gas and Iodine to give Hydrogen iodide

H₂ (g) + I₂ (g) → 2 H I(g)

ΔH∘rxn = −9.5 kJ/mol r x n

a) From the information provided, the heat of reaction being negative shows that the reaction is an exothermic reaction with the products for an exothermic reaction having a lower energy content/level as the reactants for this reaction.

This shows that the energy diagram will have the products at a lower level than fe reactants.

The sketch of the energy diagram for this exothermic reaction is presented in the first attached image to this solution.

The heat of reaction is shown on the energy diagram, together with the activation energy, Ea, the heat content/energy level for the reactants (Hr) & products (Hr) and finally the ΔH∘rxn.

ΔH∘rxn = Hp - Hr

b) When a catalyst that speed up a chemical reaction is introduced to the chemical reaction, the catalyst goes about making the reaction faster by lowering the activation energy of the reaction.

The activation energy is the minimum energy that the reactants must possess to the able to form products. On the graph, it is denoted as Ea, the difference in energy between the peak of the curve and the emergy level of the reactants.

So, a catalyst will cause this activation energy to be lowered to a new level of Ea₁.

The energy diagram of this is presented in the second attached image to this answer.

The ΔH∘rxn remains unchanged for this introduction of catalyst.

The broken lines are used to represent the lowered activation energy action of the catalyst.

c) The reverse reaction will have opposite the energy properties of the initial reaction.

The initially exothermic reaction with higher heat content of reactants than products is now an endothermic reaction with heat content/energy level of the products higher than that of the reactants.

The energy diagram is presented in the third attached image.

The activation energy is bigger and the ΔH∘rxn is now positive and equal to 9.5 kJ/mol, the direct additive inverse of the ΔH∘rxn for the initial exothermic reaction.

Hope this Helps!!!

7 0
3 years ago
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