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Rudiy27
2 years ago
13

Activity # 1: What's in the number?

Chemistry
1 answer:
Yuliya22 [10]2 years ago
8 0

Answer:nasusjs sahssjsshsgsisns shsshsksksnuw82622728

Explanation:$:hshsgsiamabsgsusisjhsshisissnsbhsussisbsvshsistsysvssjzkxjxheieuxtdbsjs

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Plz PLZ plz PLz Plz Plz Help Plz dont answer if you dont know thank you :)
Sergeeva-Olga [200]

Answer: There is no question.

Explanation:

Due to no question I can simply not answer this. Pls mark me brianliest for answering correct.

Best Regards,

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7 0
2 years ago
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4. If they..................me a question d have answered it.(ask/asked/had asked)​
LekaFEV [45]

Answer:

had asked

Explanation:

If they had asked me a question, I would have answered it.

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2 years ago
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Find the mass (in g) of 1.00 atom of lead.
Mice21 [21]

Answer:

207g

Explanation:

207.2 to be more specific

6 0
2 years ago
If 1.02 g of nickel reacted with 750. mL of 0.112 M hydrobromic acid, how much of each will be present at the end of the reactio
kati45 [8]

Answer:

35.1% is percent yield

Explanation:

<em>Full question: Assume no volume change.  If you formed 0.0910 atm of gas, what is the percent yield?</em>

<em />

The reaction that is occurring is:

Ni + 3HBr → NiBr₃ + 3/2H₂(g)

First, we will determine moles of Ni and HBr to determine limiting reactant and theoretical yield

Using ideal gas law, we can determine the moles of hydrogen formed. Thus, we can find percent yield:

<em>Moles Ni (Molar mass: 58.69g/mol):</em>

1.02g * (1mol / 58.69g) = 0.01738moles Ni

<em>Moles HBr:</em>

0.750L * (0.112mol/L) = 0.084 moles of HBr.

For a complete reaction of the 0.084 moles of HBr you need:

0.084mol HBr * (1 mole Ni / 3 moles HBr) = 0.028 moles of Ni.

As there are just 0.01738 moles of Ni, the Ni is limiting reactant. Assuming a theoretical yield, moles of H₂ produced are:

0.01738moles Ni * (3/2 H₂ / 1 mol Ni) = 0.02607 moles H₂

Now, moles of H₂ produced are:

PV = nRT

PV/RT = n

<em>Where P is pressure (0.0910atm)</em>

<em>V is volume (2.50L)</em>

<em>R is gas constant (0.082atmL/molK)</em>

<em>T is absolute temperature in Kelvin (30°C + 273.15 = 303.15K)</em>

<em>And n are moles</em>

PV/RT = n

0.0910atm*2.50L/0.082atmL/molK*303.15K = n

0.00915 moles = n

<em />

And percent yield (Produced moles / Theoretical moles * 100) is:

0.00915 moles / 0.02607moles =

<h3>35.1% is percent yield</h3>
8 0
2 years ago
Plz help (it’s a picture)
Feliz [49]
Umm I’ll figure it out rn! Will come back in 1 min
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3 years ago
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