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Rudiy27
3 years ago
13

Activity # 1: What's in the number?

Chemistry
1 answer:
Yuliya22 [10]3 years ago
8 0

Answer:nasusjs sahssjsshsgsisns shsshsksksnuw82622728

Explanation:$:hshsgsiamabsgsusisjhsshisissnsbhsussisbsvshsistsysvssjzkxjxheieuxtdbsjs

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more reliable. The more results the better results you get.

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60.0 mL of 0.0100 M H3PO4 are required to neutralize 30.0 mL of a solution of KOH. What is the molarity of the potassium hydroxi
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h2o

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Convert the volume to its equivalent in milliliters. 14 μL= ? mL
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0.014 is the answer
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What are the products of the following combustion reaction?<br><br> 2C2H2(g) + 5O2(g) →
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A combustion reaction of an  will generally produce CO2 and H20 -- carbon dioxide and water and/or an oxide

looking at the combustion material C2H2, you know that the end products will be CO2 and H20, so the question is how much of each will you get

well, look at the total amount of carbon atoms, 2 C2, which means a total of 4 carbon atoms in this reaction, since only CO2 has carbon atoms, that means there must be 4 CO2 as an end product and 4 CO2 will use up 4 of 5 O2 molecule leaving only 1 O2 molecule for the H2 reaction.

now O2 has a total of 2 oxygen molecules whereas H20 has only a single oxygen molecule, hence the end product must have 2 H20

check that the H atoms balance out on both sides
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