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Genrish500 [490]
3 years ago
6

Estimate the standard internal energy of formation of liquid methyl acetate (methyl ethanoate, ch3cooch3) at 298 k from its stan

dard enthalpy of formation, which is –442 kj mol-1.
Chemistry
2 answers:
LenKa [72]3 years ago
6 0

solution:

the reaction for formation of methyl acetate is\\CH_{3}OH+CH_{3}COOH----------->CH_{3}COOCH_{3}+H_{2}O\\standard internal energy \\\delta u=\delta H -\delta(pv)=\delta H -\delta n\times RT\\where \delta n=change in number of moles=0\\\delta u=\delta H\\=-442kj/mol

aliina [53]3 years ago
5 0

Answer : The standard internal energy of formation of liquid methyl acetate is, -432.1 kJ/mol

Explanation :

The balanced reaction of formation of liquid methyl acetate will be:

3C(s)+3H_2(g)+O_2(g)\rightarrow CH_3COOCH_3(l)

Formula used :

\Delta H=\Delta U+\Delta n_gRT

or,

\Delta U=\Delta H-\Delta n_gRT

where,

\Delta H = change in enthalpy = -442kJ/mol=-442000J/mol

\Delta U = change in internal energy = ?

\Delta n_g = change in moles = 0 - 4 = -4  (from the reaction)

R = gas constant = 8.314 J/mol.K

T = temperature = 298 K

Now put all the given values in the above formula, we get:

\Delta U=\Delta H-\Delta n_gRT

\Delta U=(-442000J/mol)-[(-4mol)\times 8.314J/mol.K\times 298K

\Delta U=-432089.712J/mol=-432.1kJ/mol

Therefore, the standard internal energy of formation of liquid methyl acetate is, -432.1 kJ/mol

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6 0
3 years ago
Equation balancing
meriva

<u>Answer:</u>

<u>For a:</u> The balanced equation is 2S(s)+3O_2(g)\rightarrow 2SO_3(g)

<u>For c:</u> The balanced equation is 2NaOH(s)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)

<u>Explanation:</u>

A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.

  • <u>For (a):</u>

The given unbalanced equation follows:

S(s)+O_2(g)\rightarrow SO_3(g)

To balance the equation, we must balance the atoms by adding 2 infront of both S(s) and SO_3 and 3 in front of O_2

For the balanced chemical equation:

2S(s)+3O_2(g)\rightarrow 2SO_3(g)

  • <u>For (b):</u>

The given balanced equation follows:

2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3(s)

The given equation is already balanced.

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The given unbalanced equation follows:

2NaOH(s)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+H_2O(l)

To balance the equation, we must balance the atoms by adding 2 infront of H_2O(l)

For the balanced chemical equation:

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4 0
3 years ago
Given the balanced equation: 2KClO₃ ---&gt; 2KCl + 3O₂ How many moles of O₂ are produced when 4.0 moles of KCl are produced?
Verizon [17]

Answer:

The answer to your question is 6.0 moles of O₂

Explanation:

Data

                      2KClO₃    ⇒     2KCl    +    3O₂

moles of O₂ = ?

moles of KCl = 4

Process

To find the number of moles of O₂, use proportions and cross multiplication.

Use the coefficients of the balanced equation.

                    2 moles of KCl ----------------- 3 moles of O₂

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-Simplification

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-Conclusion

When 4,0 moles of KCl are produced, 6.0 moles of O₂ will be produced.                          

6 0
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The answer would be 0.25 g/mL. 
I determined the density by dividing the mass by the volume which gives you the density. D = mass/volume.
<span>6 g / 24 mL = 0.25 g/mL </span>
8 0
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