Answer:
q = 2,95 10-6 C
Explanation:
The magnetic force on a particle is described by the equation
F = q v x B
Where bold indicate vectors
Let's make the vector product
vxB =![\left[\begin{array}{ccc}i&j&k\\-3&4&12\\0&0&-0.13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C-3%264%2612%5C%5C0%260%26-0.13%5Cend%7Barray%7D%5Cright%5D)
v x B = 1.20 106 [i ^ (4 0.130) - j ^ (3 0.130)]
vx B = 1.20 106 [0.52 i ^ - 0.39j ^]
As they give us the force module, let's use Pythagoras' theorem,
|v xB | =1.20 10⁶ √( 0.52² + 0.39²)
|v x B| = 1.20 10⁶ 0.65
v xB = 0.78 10⁶
Let's replace and calculate
2.30 = q 0.78 10⁶
q = 2.3 / 0.78 106
q = 2,95 10-6 C
Average speed = total distance / total time
= (81 + 88) / (2 + 2)
= 169/4
= 42.25 kilometers/hour
Let me know if you have any questions.
<span>The concept of plate tectonics regards the earth's CRUST as broken into a number of TECTONIC PLATES that are in motion relative to each other</span>
Option C is the correct answer
Answer:
x=±0.026m
Explanation:
In simple harmonic motion the maximum value of the magnitude of velocity
The speed as a function of position for simple harmonic oscillator is given by
where A is amplitude of motion
Given data
Amplitude A=3 cm =0.03 m
v=(1/2)Vmax
To find
We have asked to find position x does its speed equal half of is maximum speed
Solution
The speed of the particle the maximum speed as:
x=±(√3(0.03)/2)
x=±0.026m
