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skelet666 [1.2K]
3 years ago
9

What is the total resistance of 3 resistors of 3ohms added together in series?

Physics
1 answer:
san4es73 [151]3 years ago
8 0
In series, you just add them: R1 + R2 + R3 = Total R
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A mass of 267 g is attached to a spring and set into simple harmonic motion with a period of 0.176 s. If the total energy of the
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Answer:

(a) 7.1 m /sec

(b) 339.9 N/m

(c) 19.91 cm

Explanation:

We have given mass m = 267 gram = 0.267 kg

Time period T = 0.176 sec

Total energy of the oscillating  system = 6.74 J

We know that energy is given by

(a) Ke=\frac{1}{2}mv_{max}^2

6.74=\frac{1}{2}\times 0.267\times v_{max}^2

v_{max}=7.1m/sec

(b) Now \omega =\frac{2\pi }{T}=\frac{2\times 3.14}{0.176}=35.681rad/sec

We know that \omega =\sqrt{\frac{k}{m}}

35.68=\sqrt{\frac{k}{0.267}}

k=339.9N/m

(c) We know that energy is given by

E=\frac{1}{2}KA^2

6.74=\frac{1}{2}\times 339.9\times A^2

A=19.91cm

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3 years ago
A wire 1.0 m long experiences a magnetic force of 0.50 N due to a
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11.50

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A battery is replaced with one of lower emf. State and explain how the resistance of the lamps would have to change in order to
kow [346]

The brightness of the lamp is proportional to the current flowing through the lamp: the larger the current, the brighter the lamp.

The current flowing through the lamp is given by Ohm's law:

I=\frac{V}{R}

where

V is the potential difference across the lamp, which is equal to the emf of the battery, and R is the resistance of the lamp.

The problem says that the battery is replaced with one with lower emf. Looking at the formula, this means that V decreases: if we want to keep the same brightness, we need to keep I constant, therefore we need to decrease R, the resistance of the lamp.

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Answer:

1.63 N

Explanation:

F = GMm/r^2

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3 years ago
Question for the day!
Alex17521 [72]

Answer:

1. <--> A.

2. <--> C.

3. <--> D

4. <--> B.

explanation: i know my science!

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3 years ago
Read 2 more answers
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