Mem me e m even have. Jags. Shah. Shiv side esicjm is n meh dish so do indbbd
In the experiment of free fall bob released a bag of mass 1 lb
so here we can say that initial speed of the bag is Zero
time taken by the bag to free fall is given as
t = 1.5 s
also the acceleration of free fall is given as
a = 9.8 m/s^2
now we will use kinematics equation here for finding the distance of free fall
so the bag will fall down by total distance of 11.025 m from its initial released position.
Answer:
Per is a Latin preposition that means "through" or "by means of". Per (pronounced like "purr") is also an English preposition that can mean "for each", "to each", "by means of", or [lastly, annoyingly] "in accordance with"; somewhat interchangeably with the [even more annoying] "as per". In the example expressions here, it conveys "because of the rationale presented at/by".
Answer:
4.635 *10^12 Neutrinos
Explanation:
Here in this question, we are to determine the number of neutrinos in billions produced, given the power generated by the proton-proton cycle.
We proceed as follows;
In proton-proton cycle generates 26.7 MeV of energy and in this cycle two neutrinos are produced.
From the question, we are given that
Power P = 9.9 watts = 9.9 J/s
Watts is same as J/s
The number of proton-proton cycles required to generate E energy is N = E / E '
Where E ' = Energy generated in proton-proton cycle which is given as 26.7 Mev in the question
Converting Mev to J, we have
= 26.7 x1.6 x10 -13 J
To get the number N which is the number of proton-proton cycle required, we have;
N = 9.9 /(26.7 x1.6 x10^-13) = 2.32 * 10^12
Since we have two proton cycles( proton-proton), it automatically means 2 neutrinos will be produced.
Therefore number of neutrions produced = 2 x Number of proton-proton cycles = 2 * 2.32 * 10^12 = 4.635 * 10^12 neutrinos
Answer:
Diameter of Wire = 4.5 mm
Explanation:
First, we need to find the fractional part of the reading. The fractional part o the reading can be given by the following formula:
Fractional Part = Circular Scale Reading x Least Count
where,
Circular Scale Reading = 50
Least Count = 0.01 mm
Therefore,
Fractional Part = (50)(0.01 mm)
Fractional Part = 0.5 mm
Now, the diameter of the wire can be given by using the following formula:
Diameter of Wire = Linear Scale Reading + Fractional Part
Diameter of Wire = 4 mm + 0.5 mm
<u>Diameter of Wire = 4.5 mm</u>
