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skelet666 [1.2K]
3 years ago
9

What is the total resistance of 3 resistors of 3ohms added together in series?

Physics
1 answer:
san4es73 [151]3 years ago
8 0
In series, you just add them: R1 + R2 + R3 = Total R
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the weatherman reports the storm waves are about 2 meters high and 35 meters apart. What properties of waves is the reporter des
8_murik_8 [283]

Answer:

Amplitude and wavelength

Explanation:

- The amplitude of a wave is the maximum displacement of the wave, measured with respect to the equilibrium position (so, for a water wave it is the maximum height of the wave relative to the equilibrium position)

- The wavelength of a wave is the distance between two consecutive crests (or throughs) of a wave. So, for a water wave, it is the distance between two consecutive waves

Therefore, in the example in the problem we have:

- 2 meters corresponds to the amplitude

- 35 meters corresponds to the wavelength

6 0
2 years ago
What is the frequency of a microwave with a wavelength of 3.52 mm?
AlekseyPX

As per the question the wavelength of the microwave is given as 3.52 mm.

we are asked to calculate the frequency of the wave.

we know that microwave is a electromagnetic wave.

As per Clark Maxwell's electromagnetic theory ,every electromagnetic wave moves with a velocity equal to the velocity of light in vacuum and that is equal to 3×10^8 m/s.

From the equation of the wave,we know that velocity of wave is the product of frequency and wavelength.

Mathematically   wave velocity v=f*\lambda   where f is the frequency of the wave and \lambda is the wavelength.

As per the question \lambda=3.52 mm

                                               = 3.52*10^{-3} m

                       Here  v=c=3*10^{8} m/s

Hence frequency of the wave f=\frac{v}{\lambda}

                                                       =\frac{3*10^{8} }{3.52*10^{-3} } s^{-1}

                                                        =0.852272727272*10^{11} Hz

Here Hertz [Hz] is the unit of frequency.                      

                                             



6 0
3 years ago
Read 2 more answers
Caleb is often described as absent-minded or forgetful. He would likely benefit from
Bumek [7]

Answer:

Getting rid of outdated information from the brain.

Explanation:

In the brain, storing and losing memory are two important things in selecting and holding relevant information. Forgetting is a way of dealing with unneeded information in the brain thus absent minded individuals have an improved brain flexibility because their brain removes unwanted and unnecessary information regularly.

5 0
3 years ago
Dogs are able to hear much higher frequencies then humans are capable of detecting. For this reason the crystals that are inaudi
AVprozaik [17]

Answer:

Dogs are able to hear much higher frequencies than humans are capable of detecting. For this reason, dog whistles that are inaudible to the human ear can be heard easily by a dog. If a dog whistle has a frequency of 30,000 Hz, what is the wavelength of the sound emitted?

3 0
3 years ago
A block of mass m1 = 3.5 kg moves with velocity v1 = 6.3 m/s on a frictionless surface. it collides with block of mass m2 = 1.7
maxonik [38]
First, let's find the speed v_i of the two blocks m1 and m2 sticked together after the collision.
We can use the conservation of momentum to solve this part. Initially, block 2 is stationary, so only block 1 has momentum different from zero, and it is:
p_i = m_1 v_1
After the collision, the two blocks stick together and so now they have mass m_1 +m_2 and they are moving with speed v_i:
p_f = (m_1 + m_2)v_i
For conservation of momentum
p_i=p_f
So we can write
m_1 v_1 = (m_1 +m_2)v_i
From which we find
v_i =  \frac{m_1 v_1}{m_1+m_2}= \frac{(3.5 kg)(6.3 m/s)}{3.5 kg+1.7 kg}=4.2 m/s

The two blocks enter the rough path with this velocity, then they are decelerated because of the frictional force \mu (m_1+m_2)g. The work done by the frictional force to stop the two blocks is
\mu (m_1+m_2)g  d
where d is the distance covered by the two blocks before stopping.
The initial kinetic energy of the two blocks together, just before entering the rough path, is
\frac{1}{2} (m_1+m_2)v_i^2
When the two blocks stop, all this kinetic energy is lost, because their velocity becomes zero; for the work-energy theorem, the loss in kinetic energy must be equal to the work done by the frictional force:
\frac{1}{2} (m_1+m_2)v_i^2 =\mu (m_1+m_2)g  d
From which we can find the value of the coefficient of kinetic friction:
\mu =  \frac{v_i^2}{2gd}= \frac{(4.2 m/s)^2}{2(9.81 m/s^2)(1.85 m)}=0.49
3 0
3 years ago
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