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3 years ago

2÷8-x=24 how do I find answer

Mathematics

2 answers:

Law Incorporation [45]3 years ago

4 0

Hello !

You have to do as follow :

$2\div8-x=24\\0.25-x=24\\-x=24-0.25\\-x=23.75\\x=-23.75$

Anuta_ua [19.1K]3 years ago

4 0

$If\ 2\div8-x=24,\ then\\\\\dfrac{2}{8}-x=24\\\\\dfrac{1}{4}-x=24\ \ \ |-\dfrac{1}{4}\\\\-x=23\dfrac{3}{4}\ \ \ |\cdot(-1)\\\\x=-23\dfrac{3}{4}\\\\If\ 2\div(8-x)=24,\ then\\\\\dfrac{2}{8-x}=\dfrac{24}{1}\ \ \ \ |cross\ multiply\\\\24(8-x)=2\ \ \ |use\ distributive\ property\\\\(24)(8)-(24)(x)=2\\\\192-24x=2\ \ \ |-192\\\\-24x=-190\ \ \ |:(-24)\\\\x=\dfrac{190}{24}\\\\x=7\dfrac{22}{24}\\\\x=7\dfrac{11}{12}$

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How many ways can four people (A, B, C, D) sit in a row at a move theater if C and D must sit next to each other?

Novay_Z [31]

Answer:

24 ways in four people.

6 0

3 years ago

The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.0 minutes and

strojnjashka [21]

Answer:

P ( 5 < X < 10 ) = 1

Step-by-step explanation:

Given:-

- Sample size n = 49

- The sample mean u = 8.0 mins

- The sample standard deviation s = 1.3 mins

Find:-

Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.

Solution:-

- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:

X ~ N ( u , s /√n )

Where

s /√n = 1.3 / √49 = 0.2143

- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:

P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )

= P ( -14.93 < Z < 8.4 )

- Using standard Z-table we have:

P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1

7 0

3 years ago

An equation parallel and perpendicular to 4x+5y=19

UNO [17]

Answer:

Parallel line:

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

$y=\frac{5}{4}x-\frac{1}{2}$

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

$4x+5y=19$

we can change it into y=mx+b form

$5y=-4x+19$

$y=-\frac{4}{5}x+\frac{19}{5}$

so,

$m=-\frac{4}{5}$

Parallel line:

we know that slope of two parallel lines are always same

so,

$m'=-\frac{4}{5}$

Let's assume parallel line passes through (1,1)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-1=-\frac{4}{5}(x-1)$

now, we can solve for y

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

$m'=\frac{5}{4}$

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-2=\frac{5}{4}(x-2)$

now, we can solve for y

$y=\frac{5}{4}x-\frac{1}{2}$

4 0

3 years ago

HELP ME WITH THIS IM DESPERATE!

Oliga [24]

Answer:

i dont know but i think its 50

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

In a population distribution, a score of x=57 corresponds to z=-0.25 and a score of x=87 corresponds to z=1.25. Find the mean an

Serggg [28]

Here is dependence between scores and x-values:

$Z_i=\dfrac{X_i-\mu}{\sigma},$

where $\mu$ is the mean, $\sigma$ is standard deviation and i changes from 1 to 2.

1. When i=1, $Z_1=-0.25,\ X_1=57,$ then

$-0.25=\dfrac{57-\mu}{\sigma}.$

2. When i=2, $Z_2=1.25,\ X_2=87,$ then

$1.25=\dfrac{87-\mu}{\sigma}.$

Now solve the system of equations:

$\left\{\begin{array}{l}-0.25=\dfrac{57-\mu}{\sigma}\\ \\1.25=\dfrac{87-\mu}{\sigma}.\end{array}\right.$

$\left\{\begin{array}{l}-0.25\sigma=57-\mu\\ \\1.25\sigma=87-\mu.\end{array}\right.$

Subtract first equation from the second:

$1.25\sigma-(-0.25\sigma)=87-57,\\ \\1.5\sigma=30,\\ \\\sigma=20.$

Then

$1.25=\dfrac{87-\mu}{20},\\ \\87-\mu=25,\\ \\\mu=87-25=62.$

Answer: the mean is 62, the standard deviation is 20.

3 0

3 years ago

Read 2 more answers