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Mathematics

1 answer:

Tomtit [17]2 years ago

4 0

I may not be able to help you but i do feel your pain lol

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Which is the equation of a line that has a slope of -2/3 and passes through point (–3, –1)?

emmainna [20.7K]

Answer:

y = (-2/3)x-3

Step-by-step explanation:

Hello:

equation is the line is : y = ax+b a is a slope

y = (-2/3)x+b

passing through the point (−3;−1) : -1 =(-2/3)(-3)+b so : b = -3

y = (-2/3)x-3

second solution : you can verify (-3 ; -1) in the equation : y = (-2/3)x-3

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The equation of the line that goes through the points ( − 3 , − 9 ) and ( − 6 , − 3 ) can be written in the form y = m x + b

ivolga24 [154]

Answer:

$y=-2x-15$

Step-by-step explanation:

$y=mx+b$ .

m is the slope of the line. To find it we can do $\frac{dy}{dx}$ which is the difference between the y-coordinates divided by the difference between the x-coordinates.

So: $\frac{dy}{dx} =\frac{-9-(-3)}{-3-(-6)} =\frac{-6}{3} =-2$ . Now we have the slope, let's input a set of coordinates into the equation so that we can find the constant $b$ .