Question

A gas sample occupies 8.77 L at 20 degrees Celsius and 3.98 atm. What is

Answer 1

Answer:

1.45 mol

Explanation:

Given data

• Volume of the gas (V): 8.77 L

• Temperature of the gas (T): 20 °C

• Pressure of the gas (P): 3.98 atm

Step 1: Calculate the absolute temperature (Kelvin)

We will use the following expression.

$K = \°C + 273.15\\K = 20\°C + 273.15 = 293K$

Step 2: Calculate the number of moles (n) of the gaseous sample

We will use the ideal gas equation.

$P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T} = \frac{3.98atm \times 8.77L}{\frac{0.0821atm.L}{mol.K} \times 293K} = 1.45 mol$