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klio [65]
3 years ago
9

what is the molarity of a solution that has 1.54 moles NaCI in a 3.7L solution. How do you prepare 50ml of 0.5 M of KCI from a s

tock solution of 1.0 M KCI ( two separate questions)
Chemistry
1 answer:
dsp733 years ago
8 0

Answer:

69jtententemwntsj6e

Explanation:

uegehwhb3iejebb

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identify the reagents necessary to achieve each of the following transformations o3 dms, pcc, ch2cl, h2so4,h2o,hgso4
hoa [83]

the reagents necessary to convert alcohol to ketoneNa_2Cr_2O_7 , H_2O which involves oxidation of alcohols.

<h3>What is oxidation of alcohols?</h3>
  • Alcohol oxidation is a significant organic chemistry process. Secondary alcohols can be oxidized to produce ketones, while primary alcohols can be oxidized to produce aldehydes and carboxylic acids.
  • In contrast, tertiary alcohols cannot be oxidized without the C-C bonds in the molecule being broken.
  • In order to cause primary alcohols to oxidize into aldehydes
  1. Cr_2O_7 ^-^2 (dichromate)
  2. CrO_3/pyridine (Collins reagent)
  3. Chromium pyridinium compound (PCC)
  4. Dichromate of pyridinium (PDC, Cornforth reagent)
  5. Periodinane by Dess-Martin
  6. Oxalyl chloride with dimethylsulfoxide (DMSO) for Swern
  • oxidation of secondary alcohols to ketones
  1. Cr_2O_7 ^-^2 (dichromate)
  2. CrO_3/pyridine (Collins reagent)
  3. Chromium pyridinium compound (PCC)
  4. Dichromate of pyridinium (PDC, Cornforth reagent)
  5. Periodinane by Dess-Martin
  6. Oxalyl chloride and dimethyl sulfoxide (DMSO) (Swern oxidation)
  7. CrO_3, H_2SO_4/acetone (Jones oxidation)
  8. Acetone with aluminum isopropoxide (Oppenauer oxidation)

To learn more about oxidation of alcohols with the given link

brainly.com/question/7207863

#SPJ4

<u>Question:</u>

Identify the reagents necessary to achieve each of the following transformations

a. O_3 , DMS

b.H_2SO_4 , H_2O , HgSO_4

c.Na_2Cr_2O_7 , H_2O

d.Fe ^ {2+}, NaOH

3 0
2 years ago
Calculate the oxidation number of the iodine (I) in each compound: HIO4 = I2 = NaI = HIO3 =
Makovka662 [10]
1) in periodic acid (HIO₄), iodine has oxidation number +7, hydrogen has oxidation number +1, oxygen has -2, compound has neutral charge:
+1 + x + 4 · (-2) = 0.
x = +7.

2) in molecule of iodine (I₂), iodine has oxidation number 0, because iodine is nonpolar molecule.

3) in sodium iodide (NaI), iodine has oxidation number -1, sodium has oxidation number +1:
+1 + x = 0.
x = -1.

4) in iodic acid (HIO₃), iodine has oxidation number +5, hydrogen has oxidation number +1, oxygen has -2, compound has neutral charge:
+1 + x + 3 · (-2) = 0.
x = +5.
8 0
3 years ago
Read 2 more answers
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