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mina [271]
2 years ago
12

Weight is the downward pull of __________ on mass. What one word completes the sentence?

Chemistry
1 answer:
Andrews [41]2 years ago
5 0

Answer:

Gravity

Correct me, if I am wrong :)

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Does it require more energy to melt an ionic compound or dissolve it in water? It requires much more energy to melt it. It takes
Dmitrij [34]
Melting, due to the strong forces provided by lattice energy framework, would require more energy
6 0
3 years ago
17. Scientists analyzed data about Vesuvius in the same way that a zoologist a specimen.
Dima020 [189]

Answer:

hii there

The correct answer is option ( B )

Explanation:

hope it helps

have a nice day

7 0
3 years ago
How many moles of ammonium sulfate can be from the reaction of 30.0 mol of NH3 with H2SO4 according to the following equation: 2
marysya [2.9K]

Answer:

15 moles of  ammonium sulfate would be formed from 30 moles of ammonia.

Explanation:

Given data:

Number of moles of ammonium sulfate formed = ?

Number of moles of ammonia = 30.0 mol

Solution:

Chemical equation:

2NH₃  +   H₂SO₄  →  (NH₄)₂SO₄

Now we will compare the moles of ammonium sulfate with ammonia.

                           NH₃           :           (NH₄)₂SO₄

                             2              :               1

                            30.0          :              1/2×30.0 = 15.0 mol

So 15 moles of  ammonium sulfate would be formed from 30 moles of ammonia.

7 0
3 years ago
How many molecules of sodium oxide will be created if 275 grams of sodium reacts with excess oxygen? Given the equation: 4Na + O
ollegr [7]

Answer:

3.60 x 10^24 molecules Na2O

Explanation:

4 0
4 years ago
1.20×10−8s to nanoseconds
AveGali [126]

Answer:

There are 12 nanoseconds in 1.2\times 10^{-8}\ s.

Explanation:

We need to convert 1.2\times 10^{-8}\ s to nanoseconds.

We know that,

1\ s=10^9\ ns

Now using unitary method to solve it such that,

1.2\times 10^{-8}\ s=1.2\times 10^{-8}\ \times 10^9\\\\=1.2\times 10\\\\=12\ ns

So, there are 12 nanoseconds in 1.2\times 10^{-8}\ s.

7 0
3 years ago
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