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3 years ago

Find the simplified form of the expression. Give your answer in scientific notation. (8x10^4)(9x10^-8)

Mathematics

2 answers:

Maslowich3 years ago

8 0

7.2x10^-3 is the correct answer :)

Orlov [11]3 years ago

6 0

<span>you just have to multiply the bases. 3 x 9 = ? add the exponents of the base 10 10^8(10^7)= 10^(8+7)</span>

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Two companies manufacture a rubber material intended for use in an automotive application. The part will be subjected to abrasiv

user100 [1]

Step-by-step explanation:

Due to the time it took to solve this question, I had little time to type the answers fully

The answers are contained fully in the attachment I have uploaded.

A. H0: u1 = u2

H1: u1 not equal to u2

The t statistics was solved to be 3.03

The degree of freedom was solved to be 26

Given this information, this is a 3 tailed test, critical value at 5% = +-2.056

T stat > critical value

We therefore reject the null hypothesis at 5% and conclude they have different mean wear

The p value is calculated using excel and the result is 0.00544

We reject null at 5% since p value is less than 0.05

B. H0: u1 = u2

H1: u1>u2

Alpha = 0.05

Following a,

Test stat = 3.03

Df = 26

Critical value for 1 tailed test = 1.706

Test stat > 1.706

We reject H0 and conclude company 1 has higher mean wear.

We find p value for a right tailed distribution using excel

Tdist(3.03,26,1)

= 0.002722

We reject h0

C. Confidence interval

1.610 < u < 8.390

8 0

3 years ago

What is 9% converted to a fraction

Genrish500 [490]

Answer:

9/100

Step-by-step explanation: whatever percentage over 100 is the fraction of a percentage

7 0

3 years ago

Read 2 more answers

Solve 3x2 − 7x − 2 = 0.

Daniel [21]

The answer think will be x=4/7

Or 4-7x

8 0

3 years ago

2.300 in word form and the value of 3

Sunny_sXe [5.5K]

Two and Three Tenths is the word form of 2.300.
The 3 holds the value of Three Tenths.

8 0

3 years ago

Consider the differential equation:

Wewaii [24]

(a) Take the Laplace transform of both sides:

$2y''(t)+ty'(t)-2y(t)=14$

$\implies 2(s^2Y(s)-sy(0)-y'(0))-(Y(s)+sY'(s))-2Y(s)=\dfrac{14}s$

where the transform of $ty'(t)$ comes from

$L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)$

This yields the linear ODE,

$-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s$

Divides both sides by $-s$ :

$Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}$

Find the integrating factor:

$\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C$

Multiply both sides of the ODE by $e^{3\ln|s|-s^2}=s^3e^{-s^2}$ :

$s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}$

The left side condenses into the derivative of a product:

$\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}$

Integrate both sides and solve for $Y(s)$ :

$s^3e^{-s^2}Y(s)=7e^{-s^2}+C$

$Y(s)=\dfrac{7+Ce^{s^2}}{s^3}$

(b) Taking the inverse transform of both sides gives

$y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]$

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that $\frac{7t^2}2$ is one solution to the original ODE.

$y(t)=\dfrac{7t^2}2\implies y'(t)=7t\implies y''(t)=7$

Substitute these into the ODE to see everything checks out:

$2\cdot7+t\cdot7t-2\cdot\dfrac{7t^2}2=14$

5 0

3 years ago