Well, what you have to do is find the unit rate for each one of those prices and how you do that is by dividing each price by the downloads
so $6.25 divided by 5= $1.25
and then $17.40 divided by 12= $1.45
so that means the one with $6.25/5 downloads has a better deal!
Answer:
3.9111 km
Explanation:
The length in kilometers is equal to the meters divided by 1,000. So, if you divide 3911.1 by 1,000 that equals 3.911. You move the decimal point to the left 3 times based on the number of zeros.
Given:
Height of Mountain A = 5210 feet
Distance of Mountain A from a helicopter above the peak = 1000 feet
Angle of depression:
Mountain B to helicopter = 43 degrees
Mountain B to Mountain A = 19 degrees
First, draw an illustration and label the enumerated given values.
Observe that there are two right triangles formed:
From the triangle formed by the helicopter and Mountain B,
let x = total height of mountain B
y = leg of first triangle (helicopter and mountain b)
h = hypotenuse
Use the Pythagorean Theorem:
cos (43) = y / h
From the second triangle formed by mountain b and a,
cos (19) = (1000 + y) / h
solve for h and y
then, solve for the height of Mountain B:
x = 1000 + y + 5210
Answer:
after 75 minutes
Step-by-step explanation:
The least common multiple (LCM) of 15 and 25 is 75. It can be found a couple of ways:
1. List the factors of each number and find the product of the unique ones:
15 = 3·5
25 = 5²
The LCM is 3·5² = 75.
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2. Find the greatest common divisor (GCD) and divide the product of the numbers by that value. From the above list of factors, we see that 5 is the GCD of 15 and 25. Then the LCM is ...
15·25/5 = 75
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Or, you can simply list multiples of each number and see what the smallest number is that is in both lists:
15, 30, 45, 60, <em>75</em>, 90
25, 50, <em>75</em>, 100
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The two buses will appear together again after 75 minutes.
Answer:
no
Step-by-step explanation:
A function cannot have 2 outputs for one input.
You should only ever have on value correlate with another.
4 as x has two outputs, 0 & 3 making it not a function
