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stepladder [879]
3 years ago
12

tammy bought rolls of paper towels to give to her family members. she first gave half of her paper towels to her niece. after gi

ving to her niece, she then gave away one-fourth of what was left to her sister. finally, after giving to her sister, she gave a third of what was left to her brother. this left her with 16 paper towel rolls. how many rolls of paper towels did tammy originally buy? math
Mathematics
1 answer:
a_sh-v [17]3 years ago
6 0

Answer:

64

Step-by-step explanation:

I just took a random number, got the remaining paper towels, and divided 16 by it. Then I multiplied 16 by that number. 64 every time. Can I please have Brainliest? I just want my first Brainliest. Please??? : ( Please?

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Brenda invests $4,848 in a savings account with a fix annual interest rate of 5% compounded 2 times per year.what will the accou
Mashutka [201]

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3 years ago
Solving multi-step <br> 2(8+4c)=32 <br>c=​
professor190 [17]
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7 0
4 years ago
HELP PLEASE!!!!! 15 PTS AND BRAINLEST!!!
Schach [20]
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8 0
3 years ago
A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.
irakobra [83]

Answer:

The integral is equal to 5\sec^2(2x)+C for an arbitrary constant C.

Step-by-step explanation:

a) If u=\tan(2x) then du=2\sec^2(2x)dx so the integral becomes \int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C. (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case u=\sec(2x) hence du=2\tan(2x)\sec(2x)dx. We rewrite the integral as \int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C.

c) We use the trigonometric identity \tan(2x)^2+1=\sec(2x)^2 is part b). The value of the integral is 5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C. which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.  

3 0
3 years ago
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