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4 years ago

PLEASE ANSWERRRRRRRRRRRR

Mathematics

2 answers:

Anarel [89]4 years ago

8 0

Answer : i would say d .

Ghella [55]4 years ago

8 0

Answer:B

Step-by-step explanation:

The lines are not parallel so they will intersect at some point outside the graph and that point would be the solution.

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Candice leaves on a trip driving at 35 miles per hour. Three hours later, her sister Liz starts from the same location driving a

Natalka [10]

It would be 7 hours because 35 x 3 is 105, if she is already 105 miles from home then 35 x 7 is 245. 245 + 105 = 350. Candice would be at 350 and Liz would be at 350, so in conclusion the answer is 7 hours. :)

4 0

3 years ago

Read 2 more answers

Which of the tables represents a function? 50 points i will give braileist

agasfer [191]

Answer:

Table R

Step-by-step explanation:

Table P

Not a function as repeat input of 6 with different outputs

Table Q

Not a function as repeat input of 5 with different outputs

Table R

Function

Table S

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3 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So $\mu = 373, \sigma = 67$

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So $n = 5, s = \frac{67}{\sqrt{5}} = 29.96$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 373}{29.96}$

$Z = 1.23$

$Z = 1.23$ has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So $\mu = 526, \sigma = 107$